Vijaya Simha
Vijaya Simha

Reputation: 431

RotateTransition current angle javafx2

I'm rotating an Image using RotateTransition and if (x,y) is the position of a point on that image initially and the position will keep on changing as the image rotates. I want to know the poistion of that point at any given time. how to get that new position of the point?

    ImageView wheel= new ImageView();
    wheel.setImage(image);

    rotateTransition = new RotateTransition(Duration.seconds(10), wheel);
    rotateTransition.setFromAngle(0);
    rotateTransition.setToAngle(360);
    rotateTransition.setInterpolator(Interpolator.LINEAR);
    rotateTransition.setCycleCount(Timeline.INDEFINITE);

//Current method I'm following doesn't seems to be accurate:

    rotateTransition.currentTimeProperty().addListener(
     new ChangeListener<Duration>() {public void changed(ObservableValue<? extends Duration> ov, Duration t, Duration t1) {
            double degree = ((360 * t.toSeconds()) / 10);
            xVal.set(((120) * Math.cos(degree * (Math.PI / 180))) + 162.5);
            yVal.set(((120) * Math.sin(degree * (Math.PI / 180)) + 162.5)); 
        }

Upvotes: 3

Views: 314

Answers (1)

gontard
gontard

Reputation: 29520

To get the current angle of the rotation, you should use the rotateProperty of the ImageView :

    wheel.rotateProperty().addListener(new ChangeListener<Number>() {
        @Override
        public void changed(ObservableValue<? extends Number> observable, 
                            Number oldValue, 
                            Number newValue) {
            System.err.println("Rotation of " + newValue + " degrees");
        }
    });

Upvotes: 1

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