CODEWITHSUNDEEP
xsltxpath
Tim
Tim

Reputation: 1769

XPath code to get value in a list

lets say I have this XML :

<myxml>
    <Labels>
        <Label>
            <id>id1</id>
            <value>abc</value>
        </Label>
        <Label>
            <id>id2</id>
            <value>def</value>
        </Label>
        <Label>
            <id>id3</id>
            <value>ghi</value>
        </Label>
        <Label>
            <id>id4</id>
            <value>jkl</value>
        </Label>
        <Label>
            <id>id5</id>
            <value>mno</value>
        </Label>
    </Labels>
</myxml>

And I would like to display the value "def" and "jkl".

I'm looking for the XPath expression that allow me to take the value of a label where the id is "id2".

I've tried with this :

<xsl:value-of disable-output-escaping="yes" select="Labels/Label[id = 'id2']/value"/>

but it's not working ... Is there a way to do that ?

Thanks in advance for your answer, Best regards

Upvotes: 0

Views: 103

Answers (1)

wst
wst

Reputation: 11771

Have you tried adding the root to your xpath?

<xsl:value-of select="myxml/Labels/Label[id = 'id2']/value" />

Also, disable-output-escaping is typically unnecessary.

Upvotes: 1

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