CODEWITHSUNDEEP
python
Codenovice
Codenovice

Reputation: 31

Suggestions on improving my code.

Hello I am a fairly novice programmer. And I have a simple code 

name=raw_input("Hello I am Bob. What is your name?") 
print("It is very nice to meet you,", name) 
response=raw_input("what do you want to do today?") 
if response == "price match":

However on the fourth line I get SyntaxError: unexpected EOF while parsing error and I did look into it and I found that using the raw_input for inputted strings is much better than using the input function.I don't know why the error keeps popping up. Could I get some help and perhaps some suggestions as to how I can improve the code.

Upvotes: 1

Views: 96

Answers (3)

Daniel Williams
Daniel Williams

Reputation: 8885

If you need a placeholder for just having valid syntax before putting in the body of your if/else/functions/etc, use pass.

http://docs.python.org/release/2.5.2/ref/pass.html

As for your code, a valid if statement must always have a body. So put some code there or use pass.

Upvotes: 0

nneonneo
nneonneo

Reputation: 179422

You have to do something in the if statement. For example, print a price:

if response == "price match":
    print "Yes, we can do that for you".

But, you can't just leave a block (the stuff that is indented after a :) empty, or Python will give you an error.

In rare cases (and not in your case here), you may want to do absolutely nothing, but still have a block (e.g. if required to by an except:). In that case, you still have to put something in the block, but you can use the word pass which does nothing. (This is almost never used in an if block).

Upvotes: 2

Phorce
Phorce

Reputation: 2664

I'm no Python expert.. But it looks like your problem is here:

response=raw_input("what do you want to do today?") if response == "price match":

You are defining an if statement, but if this value is true, how do you handle it?

I'm guessing you would need something like:

if response == "price match":
  print('Match')
 else:
    print('Did not match')

Hope this helps a little

Upvotes: 1

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