CODEWITHSUNDEEP
c++function-pointers
user1679802
user1679802

Reputation: 167

call function through reference (?)

I have the following function call (myFunc() is of type double):

double value = F1->F2->myFunc();

I would like to get something that when i call value it should call F1->F2->myFunc();

With the help of the forum I got help and understood than calling a function through a variable i should do something like:

typedef double(*)() m;
m variable = myFunc;

and call it like variable();

Unfortunatly with the above setup it doesn't really work, I get a reference to &F2::myFunc but how do i get it in the above setup?

something like:

typedef double(*)() m;
m variable = &F2::myFunc; <- doesn't work :(

Thank you guys for any Help!

Upvotes: 0

Views: 113

Answers (2)

Andy Prowl
Andy Prowl

Reputation: 126522

I would like to get something that when i call value it should call F1->F2->myFunc();

In C++11, you could use a lambda:

auto l = [&] () { return F1->F2->myFunc(); };
double value = l();

Scott Meyer's update on his upcoming book Effective C++ 11 also mentions:

Prefer lambdas to std::bind.

Upvotes: 3

Some programmer dude
Some programmer dude

Reputation: 409404

You could do this with std::function and std::bind:

std::function<double()> variable = std::bind(&ClassOfF2::myFunc, F1->F2);

double value = variable();

Upvotes: 4

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