Reputation: 3029
What are the pros and cons of using this:
String a = new String();
switch (i) {
case 1: a = "Cueck"; break;
case 2: a = "Blub"; break;
case 3: a = "Writing cases is BORING!"; break;
}
System.out.println(a);
Versus:
switch (i) {
case 1: System.out.println("Cueck"); break;
case 2: System.out.println("Blub"); break;
case 3: System.out.println("Writing cases is BORING!"); break;
}
Which generates better bytecode? And which generates more bytecode?
Upvotes: 4
Views: 103
Reputation: 35018
Using javap -c classname
you can check the bytecode yourself,
Here's option 1:
(Note, I had to initialise a = null
otherwise it doesn't compile)
7: aconst_null
8: astore_2
9: iload_1
10: tableswitch{ //1 to 3
1: 36;
2: 42;
3: 48;
default: 51 }
36: ldc #3; //String Cueck
38: astore_2
39: goto 51
42: ldc #4; //String Blub
44: astore_2
45: goto 51
48: ldc #5; //String Writing cases is BORING!
50: astore_2
51: getstatic #6; //Field java/lang/System.out:Ljava/io/PrintStream;
54: aload_2
55: invokevirtual #7; //Method java/io/PrintStream.println:(Ljava/lang/String;)V
58: return
Here's option 2:
7: iload_1
8: tableswitch{ //1 to 3
1: 36;
2: 47;
3: 58;
default: 66 }
36: getstatic #3; //Field java/lang/System.out:Ljava/io/PrintStream;
39: ldc #4; //String Cueck
41: invokevirtual #5; //Method java/io/PrintStream.println:(Ljava/lang/String;)V
44: goto 66
47: getstatic #3; //Field java/lang/System.out:Ljava/io/PrintStream;
50: ldc #6; //String Blub
52: invokevirtual #5; //Method java/io/PrintStream.println:(Ljava/lang/String;)V
55: goto 66
58: getstatic #3; //Field java/lang/System.out:Ljava/io/PrintStream;
61: ldc #7; //String Writing cases is BORING!
63: invokevirtual #5; //Method java/io/PrintStream.println:(Ljava/lang/String;)V
66: return
Personally, I don't think there's better bytecode in this instance, I find option 1 more readable.
Upvotes: 4
Reputation: 69339
Your first option is neater and has less redundant code. One suggested change:
String a;
switch (i) {
case 1: a = "Cueck"; break;
case 2: a = "Blub"; break;
case 3: a = "Writing cases is BORING!"; break;
default: throw new IllegalStateException("Unknown option!");
}
System.out.println(a);
Don't create a String unnecessarily - a
should be instatiated when required. A default case should either throw an exception or set a
to a default value.
Which generates better bytecode? And which generates more bytecode?
I wouldn't worry about that. This doesn't strike me as a likely bottleneck in any real-life application. Also, you cannot be sure what the JVM will do to optimise the byte-code once your application is running.
Upvotes: 5
Reputation: 14277
I don't think there will be much difference in bytecode size but I suggest first approach. If you in some future code changes decide not to call System.out.println(a)
but logger.debug(a)
you will change that only on one place and not on all case
switches.
Upvotes: 4