CODEWITHSUNDEEP
c#xmlxpathyoutubenamespaces
Bullman
Bullman

Reputation: 328

XmlNode in XmlNodelist

Does anyone know where is mistake? Or is better way to get video name into string?

string text = "<?xml version='1.0' encoding='UTF-8'?><feed xmlns='http://www.w3.org/2005/Atom' xmlns:media='http://search.yahoo.com/mrss/' xmlns:openSearch='http://a9.com/-/spec/opensearchrss/1.0/' xmlns:gd='http://schemas.google.com/g/2005' xmlns:yt='http://gdata.youtube.com/schemas/2007'><entry><title>VIDEO NAME</title></entry></feed>";
string xpath = "feed/entry";
XmlDocument xml = new XmlDocument();
xml.LoadXml(text);
XmlNodeList nodes = xml.SelectNodes(xpath);
foreach (XmlNode node in nodes)
{
    string title = node["title"].InnerText;
    MessageBox.Show(title);
}

XML

<?xml version='1.0' encoding='UTF-8'?>
    <feed xmlns='http://www.w3.org/2005/Atom' xmlns:media='http://search.yahoo.com/mrss/' xmlns:openSearch='http://a9.com/-/spec/opensearchrss/1.0/' xmlns:gd='http://schemas.google.com/g/2005' xmlns:yt='http://gdata.youtube.com/schemas/2007'>
      <entry>
        <title>VIDEO NAME</title>
      </entry>
    </feed>

Upvotes: 0

Views: 9814

Answers (3)

dkackman
dkackman

Reputation: 15579

This declaration in the Xml xmlns='http://www.w3.org/2005/Atom' puts all elements in the document that don't have a namespace prefix in the default namespace http://www.w3.org/2005/Atom/. Therefore you need to use namespaces in your XPath queries:

        string text = "<?xml version='1.0' encoding='UTF-8'?><feed xmlns='http://www.w3.org/2005/Atom' xmlns:media='http://search.yahoo.com/mrss/' xmlns:openSearch='http://a9.com/-/spec/opensearchrss/1.0/' xmlns:gd='http://schemas.google.com/g/2005' xmlns:yt='http://gdata.youtube.com/schemas/2007'><entry><title>VIDEO NAME</title></entry></feed>";

        XmlDocument xml = new XmlDocument();
        xml.LoadXml(text);
        XmlNamespaceManager nsmgr = new System.Xml.XmlNamespaceManager(xml.NameTable);
        nsmgr.AddNamespace("atom", "http://www.w3.org/2005/Atom");
        string xpath = "atom:feed/atom:entry/atom:title";
        XmlNodeList nodes = xml.SelectNodes(xpath, nsmgr);

        foreach (XmlNode node in nodes)
        {
            Console.WriteLine(node.InnerText);
        }

Upvotes: 3

MarcinJuraszek
MarcinJuraszek

Reputation: 125650

You can use LINQ to XML instead of XmlDocument and XPath:

string text = "<?xml version='1.0' encoding='UTF-8'?><feed xmlns='http://www.w3.org/2005/Atom' xmlns:media='http://search.yahoo.com/mrss/' xmlns:openSearch='http://a9.com/-/spec/opensearchrss/1.0/' xmlns:gd='http://schemas.google.com/g/2005' xmlns:yt='http://gdata.youtube.com/schemas/2007'><entry><title>VIDEO NAME</title></entry></feed>";
var doc = XDocument.Parse(text);
var atom = XNamespace.Get("http://www.w3.org/2005/Atom");

var titles = doc.Descendants(atom + "entry")
                .Select(e => (string)e.Element(atom + "title"))
                .ToList();

foreach (string title in titles)
    Console.WriteLine(title);

Upvotes: 1

Adam
Adam

Reputation: 16199

This works but the code I produced feels like such a dirty hack

        string text = "<?xml version='1.0' encoding='UTF-8'?><feed xmlns='http://www.w3.org/2005/Atom' xmlns:media='http://search.yahoo.com/mrss/' xmlns:openSearch='http://a9.com/-/spec/opensearchrss/1.0/' xmlns:gd='http://schemas.google.com/g/2005' xmlns:yt='http://gdata.youtube.com/schemas/2007'><entry><title>VIDEO NAME</title></entry></feed>";
        XmlDocument xml = new XmlDocument();
        xml.LoadXml(text);
        XmlNode parentNode = xml.GetElementsByTagName("feed").Item(0);
        foreach (XmlNode n in parentNode.ChildNodes)
        {
            string title = n["title"].InnerText;
            Console.WriteLine(title);
        }

        Console.ReadLine();

Upvotes: 0

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