CODEWITHSUNDEEP
ruby-on-railsrubyregexruby-on-rails-3
user1971993
user1971993

Reputation:

How to detect if (number + chars (not number))

How would I detect if I have this scenario, I would be getting this inputs 

3b => allow
4b => allow
55b => allow
1111bbbb => allow
num45 => no !

and if I do allow given, I wold also like to remove all characters that are not numbers 

3b => 3
555B => 555
11 => 11

I have tried to check if the given input is numeric or not, but this condition is out of scope of my knowledge.

Thanks for your time and consideration.

Upvotes: 0

Views: 100

Answers (5)

Sam
Sam

Reputation: 3067

This will look for integer + string and convert it to an integer. It will ignore a string + integer input.

input = '45num'

if input.match(/\d+[a-zA-Z]+/)
  result = input.to_i
end

result => 45

Upvotes: 2

Qtax
Qtax

Reputation: 33908

You can use:

/\A(\d+)[a-z]*\z/i

If the expression matches your desired number will be in the first capturing group.

Example at Rubular. (It uses ^/$ instead of \A/\z just for the demonstration, you should use \A/\z.)

Upvotes: 2

pguardiario
pguardiario

Reputation: 54984

You really want to use: str[/\A\d+/] - This will give you the leading digits or nil.

Upvotes: 1

Zippie
Zippie

Reputation: 6088

if the string begins with a number 

!/^[0-9]/.match(@variable).nil?

if it does, get only the number part

   @variable = @variable.gsub(/[^0-9]/, '')

Upvotes: -1

Saurabh Sharma
Saurabh Sharma

Reputation: 2341

Hmm I am no regex ninja but I think you could use: ^([\d]+) to capture JUST the number. give it a try here

Upvotes: 0

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