CODEWITHSUNDEEP
c++classfriend
Macaire Alexander Bell
Macaire Alexander Bell

Reputation: 41

Friend Function, expected Primary Expression before . token

So there are two classes in separate header files

Customer. h

using namespace std;
#include <iostream>

class Customer{
    friend void Display();
private:
    int number, zipCode;
public:
    Customer(int N, int Z){
    number = N;
    zipCode = Z;
    }
};

City. h using namespace std; #include #include "Customer.h"

class City{
    friend void Display();
private:
    int zipCode;
    string city, state;
public:
    City(int Z, string C, string S){
        zipCode = Z;
        city = C;
        state = S;
    }
};

my main.cpp is as follows

#include "City.h"
#include "Customer.h"

void Display(){
        cout<<"Identification Number: "<<Customer.number<<endl
                <<"Zip Code: "<<Customer.zipCode<<endl
                <<"City: "<<City.city<<endl
                <<"State: "<<City.state<<endl;
    }


int main() {
    Customer A(1222422, 44150);
    City B(44150, "Woklahoma", "Kansas");

    Display();

}

I'm good with the basics of c++ but this is where I Don't understand, so my specific question is.... Why for the four lines of my Display function does the compiler tell me "error: expected primary-expression before ‘.’ token"

Thanks in advance, Macaire

Upvotes: 0

Views: 642

Answers (2)

Joseph Mansfield
Joseph Mansfield

Reputation: 110658

Customer is a type. You need an object of that type to access it's number member (and the same for the rest of the lines).

You probably meant to take a Customer and City as arguments to Display:

void Display(Customer customer, City city){
    cout<<"Identification Number: "<<customer.number<<endl
            <<"Zip Code: "<<customer.zipCode<<endl
            <<"City: "<<city.city<<endl
            <<"State: "<<city.state<<endl;
}

Then pass your Customer and City objects to that function:

Display(A, B);

Upvotes: 1

juanchopanza
juanchopanza

Reputation: 227418

You are attempting to access data members from a class name

Customer.number

You cannot do that. You need a Customer instance:

Customer c;
std::cout << c.number;

You probably want to change Display() to

void Display(const Customer& c);

then use it like this:

Customer A(1222422, 44150);
Display(A);

and similarly for City.

Upvotes: 1

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