CODEWITHSUNDEEP
javazipzipinputstream
peter.murray.rust
peter.murray.rust

Reputation: 38033

extracting contents of ZipFile entries when read from byte[] (Java)

I have a zip file whose contents are presented as byte[] but the original file object is not accessible. I want to read the contents of each of the entries. I am able to create a ZipInputStream from a ByteArrayInputStream of the bytes and can read the entries and their names. However I cannot see an easy way to extract the contents of each entry.

(I have looked at Apache Commons but cannot see an easy way there either).

UPDATE @Rich's code seems to solve the problem, thanks

QUERY why do both examples have a multiplier of * 4 (128/512 and 1024*4) ?

Upvotes: 5

Views: 8531

Answers (3)

ZZ Coder
ZZ Coder

Reputation: 75456

It's a little bit tricky to calculate the start of next ZipEntry. Please see this example included in JDK 6,

public static void main(String[] args) {
    try {
        ZipInputStream is = new ZipInputStream(System.in);
        ZipEntry ze;
        byte[] buf = new byte[128];
        int len;

        while ((ze = is.getNextEntry()) != null) {
            System.out.println("----------- " + ze);

            // Determine the number of bytes to skip and skip them.
            int skip = (int)ze.getSize() - 128;
            while (skip > 0) {
                skip -= is.skip(Math.min(skip, 512));
            }

            // Read the remaining bytes and if it's printable, print them.
            out: while ((len = is.read(buf)) >= 0) {
                for (int i=0; i<len; i++) {
                    if ((buf[i]&0xFF) >= 0x80) {
                        System.out.println("**** UNPRINTABLE ****");

                        // This isn't really necessary since getNextEntry()
                        // automatically calls it.
                        is.closeEntry();

                        // Get the next zip entry.
                        break out;
                    }
                }
                System.out.write(buf, 0, len);
            }
        }
        is.close();
    } catch (Exception e) {
        e.printStackTrace();
    }
}

Upvotes: 1

Rich Seller
Rich Seller

Reputation: 84028

If you want to process nested zip entries from a stream, see this answer for ideas. Because the inner entries are listed sequentially they can be processed by getting the size of each entry and reading that many bytes from the stream.

Updated with an example that copies each entry to Standard out:

ZipInputStream is;//obtained earlier

ZipEntry entry = is.getNextEntry();

while(entry != null) {
    copyStream(is, out, entry);

    entry = is.getNextEntry();
}
...

private static void copyStream(InputStream in, OutputStream out,
        ZipEntry entry) throws IOException {
    byte[] buffer = new byte[1024 * 4];
    long count = 0;
    int n = 0;
    long size = entry.getSize();
    while (-1 != (n = in.read(buffer)) && count < size) {
        out.write(buffer, 0, n);
        count += n;
    }
}

Upvotes: 6

Tom Hawtin - tackline
Tom Hawtin - tackline

Reputation: 147124

It actually uses the ZipInputStream as the InputStream (but don't close it at the end of each entry).

Upvotes: 0

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