CODEWITHSUNDEEP
xtextxtend
moin moin
moin moin

Reputation: 2453

how to use the script xtext name in generator

I want to use the script-name in the generator to create the corresponding java file. For example if my script file would be "WordCount.script" I want to create a "WordCount.java" file. I found out the previous versions exposed this via "resource.className" but it did not work for 2.3.1.

override void doGenerate(...

   fsa.generateFile(magic_here + ".java", compile...)

Upvotes: 2

Views: 934

Answers (3)

Colonel Panic
Colonel Panic

Reputation: 999

You can access the normalized URI for your Resource using ECoreUtil2. For example;

import static extension org.eclipse.xtext.EcoreUtil2.*

....
override void doGenerate(Resource input...

    fsa.generateFile(input.normalizedURI.lastSegment + ".java", compile...)

Or, if you want an absolute path, you can leave off the lastSegment. You may want to strip the filename off the end (".mydsl" for example) before generation, such as in:

    fsa.generateFile(input.normalizedURI.replace(".mydsl", ".java), compile...

Whatever suits your use case!

Upvotes: 4

Charles Henry
Charles Henry

Reputation: 373

Here is an example:

 fsa.generateFile(
    "src"+"/"+"com"+"/"+"stackoverflow"+"/"+"magic"+"/"+ //package
    "more_magic"+".java", //class name
    compile...)

The package will be in the src folder and will be 'com.stackoverflow.magic' You will only see it as a package once you import the files into a project.

Upvotes: 0

Sebastian Zarnekow
Sebastian Zarnekow

Reputation: 6729

The resource has a property URI that encapsulates the name of the file. You may want to access the #lastSegment of it to compute the name of the Java file.

Upvotes: 0

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