CODEWITHSUNDEEP
javascriptregex
Vindhya G
Vindhya G

Reputation: 1369

matching regular expression with semicolon in sentences

here is a program to match a regular expression

string="Mozilla/5.0 (Series40; NOKIA311/03.81; Profile/MIDP-2.1 Configuration/CLDC-1.1) Gecko/20100401 S40OviBrowser/2.2.0.0.31";
regex=/(nokia).*([a-zA-Z0-9]+)/i
regex.exec(string)

My problem is its not matching to NOKIA and 311

Could anyone help.please

Upvotes: 0

Views: 1132

Answers (2)

Explosion Pills
Explosion Pills

Reputation: 191799

The problem is the .*, which tries to match as much as possible. It actually ends up matching the entire rest of the string and only leaves the 1 from the very end to satisfy the [a-zA-Z0-9]+. You need a more specific regex, perhaps:

/nokia(\d+)/i
/nokia(.*?)\//i

The .*? makes the .* reluctant, so it will only match up to the first slash.

Upvotes: 2

Ahmed Aeon Axan
Ahmed Aeon Axan

Reputation: 2139

use the regex /NOKIA([\d\w]*)/i

Which will match the pattern NOKIA and any number or word without spaces

Upvotes: 0

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