CODEWITHSUNDEEP
c++compiler-errorsoperator-overloadingoverloading
Kudayar Pirimbaev
Kudayar Pirimbaev

Reputation: 1320

C++: Compiler doesn't see overloaded operator

I have stuck on my try to implement linked list iterator class. Compiler is complaining when I use overloaded "!=" operator here:

for (itr = (test0.begin()); itr != (test0.end()); ++itr)
{
    cout << *itr;
}

Here is the error:

error: no match for ‘operator!=’ in ‘itr != SinglyLinkedList<Object>::end() [with Object = int]()’

I don't understand why it can't find the match, because both test0.end() and itr are iterators.

Here is the code of overloaded operator:

bool operator!= (iterator &rhs)
{
    return (this->current != rhs.current);
}

Thanks in advance.

Upvotes: 1

Views: 942

Answers (1)

wilx
wilx

Reputation: 18228

I suspect that this is because of const-correctness:

bool operator!= (iterator const &rhs) const
{
    return (this->current != rhs.current);
}

Upvotes: 5

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