Reputation: 986
I want to convert HashMap to json array my code is as follow:
Map<String, String> map = new HashMap<String, String>();
map.put("first", "First Value");
map.put("second", "Second Value");
I have tried this but it didn't work. Any solution?
JSONArray mJSONArray = new JSONArray(Arrays.asList(map));
Upvotes: 24
Views: 73509
Reputation: 20155
Try this,
public JSONObject (Map copyFrom)
Creates a new JSONObject by copying all name/value mappings from the given map.
Parameters copyFrom a map whose keys are of type String and whose values are of supported types.
Throws NullPointerException if any of the map's keys are null.
Basic usage:
JSONObject obj=new JSONObject(yourmap);
get the json array from the JSONObject
Edit:
JSONArray array=new JSONArray(obj.toString());
Edit:(If found Exception then You can change as mention in comment by @krb686)
JSONArray array=new JSONArray("["+obj.toString()+"]");
Upvotes: 49
Reputation: 1871
Since androiad API Lvl 19, you can simply do new JSONObject(new HashMap())
. But on older API lvls you get ugly result(simple apply toString to each non-primitive value).
I collected methods from JSONObject and JSONArray for simplify and beautifully result. You can use my solution class:
package you.package.name;
import org.json.JSONArray;
import org.json.JSONException;
import org.json.JSONObject;
import java.lang.reflect.Array;
import java.util.Collection;
import java.util.Map;
public class JsonUtils
{
public static JSONObject mapToJson(Map<?, ?> data)
{
JSONObject object = new JSONObject();
for (Map.Entry<?, ?> entry : data.entrySet())
{
/*
* Deviate from the original by checking that keys are non-null and
* of the proper type. (We still defer validating the values).
*/
String key = (String) entry.getKey();
if (key == null)
{
throw new NullPointerException("key == null");
}
try
{
object.put(key, wrap(entry.getValue()));
}
catch (JSONException e)
{
e.printStackTrace();
}
}
return object;
}
public static JSONArray collectionToJson(Collection data)
{
JSONArray jsonArray = new JSONArray();
if (data != null)
{
for (Object aData : data)
{
jsonArray.put(wrap(aData));
}
}
return jsonArray;
}
public static JSONArray arrayToJson(Object data) throws JSONException
{
if (!data.getClass().isArray())
{
throw new JSONException("Not a primitive data: " + data.getClass());
}
final int length = Array.getLength(data);
JSONArray jsonArray = new JSONArray();
for (int i = 0; i < length; ++i)
{
jsonArray.put(wrap(Array.get(data, i)));
}
return jsonArray;
}
private static Object wrap(Object o)
{
if (o == null)
{
return null;
}
if (o instanceof JSONArray || o instanceof JSONObject)
{
return o;
}
try
{
if (o instanceof Collection)
{
return collectionToJson((Collection) o);
}
else if (o.getClass().isArray())
{
return arrayToJson(o);
}
if (o instanceof Map)
{
return mapToJson((Map) o);
}
if (o instanceof Boolean ||
o instanceof Byte ||
o instanceof Character ||
o instanceof Double ||
o instanceof Float ||
o instanceof Integer ||
o instanceof Long ||
o instanceof Short ||
o instanceof String)
{
return o;
}
if (o.getClass().getPackage().getName().startsWith("java."))
{
return o.toString();
}
}
catch (Exception ignored)
{
}
return null;
}
}
Then if you apply mapToJson() method to your Map, you can get result like this:
{
"int": 1,
"Integer": 2,
"String": "a",
"int[]": [1,2,3],
"Integer[]": [4, 5, 6],
"String[]": ["a","b","c"],
"Collection": [1,2,"a"],
"Map": {
"b": "B",
"c": "C",
"a": "A"
}
}
Upvotes: 16
Reputation: 4971
This is the Simplest Method.
Just use
JSONArray jarray = new JSONArray(hashmapobject.toString);
Upvotes: 2
Reputation: 33749
A map consists of key / value pairs, i.e. two objects for each entry, whereas a list only has a single object for each entry. What you can do is to extract all Map.Entry<K,V> and then put them in the array:
Set<Map.Entry<String, String> entries = map.entrySet();
JSONArray mJSONArray = new JSONArray(entries);
Alternatively, sometimes it is useful to extract the keys or the values to a collection:
Set<String> keys = map.keySet();
JSONArray mJSONArray = new JSONArray(keys);
or
List<String> values = map.values();
JSONArray mJSONArray = new JSONArray(values);
Note: If you choose to use the keys as entries, the order is not guaranteed (the keySet()
method returns a Set
). That is because the Map
interface does not specify any order (unless the Map
happens to be a SortedMap
).
Upvotes: 3