Reputation: 15720
ArrayList<String> dirNo = new ArrayList<String>();
dirNo.add("1");
dirNo.add("2");
dirNo.add("3");
dirNo.add("4");
dirNo.add("5");
dirNo.add("6");
dirNo.add("7");
dirNo.add("8");
dirNo.add("9");
dirNo.add("10");
dirNo.add("11");
System.out.println("max : " + Integer.parseInt(Collections.max(dirNo)));
After executing above code, print 9 as output.
But actually max value should be 11.
Why am I getting 9 as max ?
Upvotes: 12
Views: 20060
Reputation: 3
this should work fine
String[] allLongestStrings(String[] inputArray) {
ArrayList<String> newArray = new ArrayList<String>();
ArrayList<Integer> arrayIndex = new ArrayList<Integer>();
ArrayList<String> longestString = new ArrayList<String>();
for(int i=0; i < inputArray.length;i++){
newArray.add(inputArray[i]);
arrayIndex.add(inputArray[i].length());
}
int maximumVal = Collections.max(arrayIndex);
for(int j=0; j < newArray.size();j++){
if(newArray.get(j).length() >= maximumVal){
longestString.add(newArray.get(j));
}
}
String[] stringArray = longestString.toArray(new
String[longestString.size()]);
return stringArray;
}
Upvotes: 0
Reputation: 55
Change String to Integer
ArrayList<Integer> dirNo = new ArrayList<Integer>();
That's it.
Upvotes: 0
Reputation: 22271
You are using a String collection! String comparison is completely different from number comparsion.
String value "2" > "11"
because '2' > '1'
(first character difference)
Upvotes: 1
Reputation: 500733
Since your elements are strings, Collections.max()
is returning the value that's the largest lexicographically.
If you wish to compare the strings numerically, you need to use the two-argument version of Collections.max()
and supply an appropriate comparator:
ArrayList<String> dirNo = new ArrayList<String>();
dirNo.add("1");
dirNo.add("2");
dirNo.add("3");
dirNo.add("4");
dirNo.add("5");
dirNo.add("6");
dirNo.add("7");
dirNo.add("8");
dirNo.add("9");
dirNo.add("10");
dirNo.add("11");
Comparator<String> cmp = new Comparator<String>() {
@Override
public int compare(String o1, String o2) {
return Integer.valueOf(o1).compareTo(Integer.valueOf(o2));
}
};
System.out.println("max : " + Collections.max(dirNo, cmp));
Upvotes: 35