CODEWITHSUNDEEP
php
Francesco
Francesco

Reputation: 25239

Does PHP 5.3.3 ignore my code or what?

i'm using a very simple code

<? if ($_GET["end"]=='1') { ?>
    <div id="header-message">
        this is the message
    </div>
<?  } ?>

in my company server the code is ignored and the browser displays the DIV

on my personal server the message is not displayed unless the variable $end is !=""

i'm having hard time what can cause this issue...is a difference in phph 5.3.3 vs 5.4?? or else? or may code is wrong??

Upvotes: 0

Views: 89

Answers (3)

Marco Acierno
Marco Acierno

Reputation: 14847

Try this: if ($_GET["end"]==1) instead of '1'.. if your php.ini allows short tags his code should work with too.

Maybe is read as integer in a case and as string in another.

Upvotes: 0

Marin Sagovac
Marin Sagovac

Reputation: 3972

1 means true but "1" is a string or '1'. So you use only 1 or true for check is true.

And use full tag <?php ... ?> instead short <? ... ?>

Upvotes: 0

Kyle
Kyle

Reputation: 4449

Most likely, it is because you are missing the php portion of your php tag.

<? if ($_GET["end"]=='1') { ?>
    <div id="header-message">
        this is the message
    </div>
<?  } ?>

Becomes

<?php if ($_GET["end"]=='1') { ?>
    <div id="header-message">
        this is the message
    </div>
<?php  } ?>

UPDATE

As others have stated, the first option is valid if you have the short_open_tag directive on. Please also be aware that as of PHP 5.4.0, you do not need to specify the short_open_tag directive.

Upvotes: 2

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