Reputation: 8770
I have an image in a WPF window with the default Stretch
setting, Uniform, and am making an attempt to make it fill the screen horizontally. I do not wish to use a different Stretch
setting as this is supposed to a learning experience. The image dimensions being loaded are 420x800
. This is the XAML for the window..
<Window x:Class="WpfApplication1.MainWindow"
xmlns="http://schemas.microsoft.com/winfx/2006/xaml/presentation"
xmlns:x="http://schemas.microsoft.com/winfx/2006/xaml"
Background="Red" Height="1200" Width="840">
<Image Name="Image" Source="{Binding SourceUri}">
<Image.RenderTransform>
<TransformGroup>
<ScaleTransform x:Name="Scale" />
<TranslateTransform x:Name="Translate" />
</TransformGroup>
</Image.RenderTransform>
</Image>
</Window>
On the code-behind, I am attempting to calculate the scaling to zoom the image to fill the horizontal screen and I am using translate transform the move it to the center of the screen. The following bit of code is obviously wrong...
using System.Windows;
using System.Windows.Controls;
using System.Windows.Media;
namespace WpfApplication1 {
public partial class MainWindow : Window {
public MainWindow() {
InitializeComponent();
DataContext = this;
double ImageWidth = 420;
Scale.ScaleX = Width / ImageWidth;
Translate.X = -(ImageWidth / 2);
}
public string SourceUri {
get {
return @"C:\Users\Roel\Desktop\test.png";
}
}
}
}
I am attempting to understand how stretching and transformations are working together but I am having difficulty with this. I would appreciate all insights, even references to detailed explanations, as I have trouble finding any informational source explaining clearly and concisely how the transformations are applied.
Upvotes: 0
Views: 12191
Reputation: 128061
You would usually just do this:
<Image Name="Image" Source="{Binding SourceUri}" Stretch="Fill"/>
In case you really need to calculate the stretch transformation manually, you would only need a ScaleTransform
, no TranslateTransform
, and you would put that into the LayoutTransform
of the Image control. Moreover, the Image control would have to be placed into a Grid, which provides the size of the Windows's "client area". You can't calculate anything based on the Window's Width (or ActualWidth) as that includes the width of the Window's borders.
<Grid SizeChanged="Grid_SizeChanged">
<Image Name="image" Source="{Binding SourceUri}">
<Image.LayoutTransform>
<ScaleTransform x:Name="scale"/>
</Image.LayoutTransform>
</Image>
</Grid>
In the Grid's SizeChanged handler you would calculate the scaling as shown below.
private void Grid_SizeChanged(object sender, SizeChangedEventArgs e)
{
scale.ScaleX = e.NewSize.Width / image.Source.Width;
scale.ScaleY = e.NewSize.Height / image.Source.Height;
}
Upvotes: 2