CODEWITHSUNDEEP
javaregex
Kevin
Kevin

Reputation: 2291

How to use Java Regex to put a particular string into array?

How can I put the "no", "no", "0.002", "0.998" below into the String array with regex in Java?

 String lines = "     1       2:no       2:no       0.002,*0.998"

Could someone please tell me how to write "theRegex" below? 

String[] matches = lines.split(theRegex); // => ["no", "no", "0.002", "0.998"]

In Python, it will be just one line: 

matches = line =~ /\d:(\w+).*\d:(\w+).*\((\w+)\)/

But how about Java?

Upvotes: 1

Views: 166

Answers (3)

Javier
Javier

Reputation: 12398

theRegex="[\\s,*]+" (one or more spaces, commas or asterisk)

Input 1 2:no 2:no 0.002,*0.998 Output ["1","2:no","2:no","0.002","0.9"]

Edit

The input String is " 1 2:no 2:no 0.002,*0.998", and the expected output is ["no", "no", "0.002", "0.998"]

In that case it is not possible to use split alone, because for ignoring 1 you need to treat \d as a delimiter, but \d is also part of the data in 0.002.

What you can do is: 

   Pattern pattern = Pattern.compile("^\\d(?:$|:)");
   String[] matches = lines.trim().split("[\\s,*]+");
   List<String> output = new LinkedList<String>(Arrays.asList(matches));
   for (Iterator<String> it=output.iterator(); it.hasNext();) {
     if (Pattern.matcher(it.next()).find()) it.remove();
   }

find("^\\d(?:$|:") matches strings of the form digit or digit:whatever. Note that the pattern is compiled once, then it is applied to the strings in the list. For each string one has to construct a matcher.

Upvotes: 2

MG_Bautista
MG_Bautista

Reputation: 2653

Try this regex...

(^\d|[\d]:|[\\s, *]+)+

Upvotes: 1

Achintya Jha
Achintya Jha

Reputation: 12843

String s = "1       2:no       2:no       0.002,*0.998";
String[] arr = s.split(" +");

Upvotes: 0

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