CODEWITHSUNDEEP
javaregexstringsplit
AKIWEB
AKIWEB

Reputation: 19622

Matching the ID with another String by splitting it or using regular expression

Below are the sample examples of string. In the below four string example, you will find userId as a key always.

{siteRebateSenstvty=0;1,1;2, siteRedemptChg=16;30,77;40, userId=101}
{sgmntId=1, userId=101}
{predictedCatRev=0;101;1,1;201;2, predictedOvrallRev=77;2,0;1,16;3, sitePrftblty=77;2,0;1671679, topByrGms=12345.67, usrCurncy=1, vbsTopByrGmb=167167.67, userId=101}
{zipCode=CA11 9QL, userId=101}

So now in my below method, I am trying to validate str value with id, I will be passing string and id to isStringValid method.

private boolean isStringValid(String str, String id) {
    boolean valid = false;

    System.out.println(str);

    return valid;
}

Problem Statement:-

Now I am trying to match id value with userId value in the above JSON String. Meaning if id value is 101 then in the above JSON String userId value should also be 101. If any of them doesn't matches or userId value is not there in the string then set the vaild boolean to false.

What is the best way to do this problem?

I cannot do it like this-

if(str.contains(id)) because it might be possible 101 is present as some number in any keys.

Upvotes: 0

Views: 119

Answers (1)

assylias
assylias

Reputation: 328735

Assuming that the id (101 in your first example) is always followed by ; , or }, you could use:

String str = "{siteRebateSenstvty=0;1,1;2, siteRedemptChg=16;30,77;40, userId=101}";
String id = "101";
boolean valid = str.matches(".*userId=" + id + "[,;}]+.*");
System.out.println("valid = " + valid);

The [,;}]+ part ensures that the next character is not part of the ID (so that 1015a is not considered a valid userId when you expect 101 for example).

Alternatively and probably more robust, you could use a word boundary:

boolean valid = str.matches(".*userId=" + id + "\\b+.*");

Upvotes: 1

Related Questions