Reputation: 2453
I am new to shell scripting world.
I wrote a bash shell script.
Name of the script is new.sh
Select T1.date as dateFact,
T2.idmfg as idMfg,
T1.id as userId,
FROM Table1 T1
JOIN
Table2 T2
ON
T1.id=T2.id
WHERE
T1.date ='${Date}'
T2.idmfg='${idMfg}';
While running new.sh, I want to enter Date
and idMfg
manually. E.g.
sh new.sh -d 2013-03-20 -i 201
Where, Date
is 2013-03-20
and idMfg
is 201
.
How can I do it?
Thank you in advance.
Upvotes: 0
Views: 2614
Reputation: 185053
#!/bin/bash
Date="$1"
idMfg="$2"
mysql<<EOF
SELECT T1.date AS dateFact, T2.idmfg AS idMfg, T1.id AS userId
FROM Table1 T1
JOIN Table2 T2
ON T1.id=T2.id
WHERE T1.date = "${Date}", T2.idmfg = "${idMfg}";
EOF
Usage :
./new.sh 2013-03-20 201
To go further if you want named switches, see the tutorial: http://wiki.bash-hackers.org/howto/getopts_tutorial Examples: http://mywiki.wooledge.org/BashFAQ/035
Upvotes: 4
Reputation: 17258
new.sh 2013-03-20 201
Inside the script the first (date) param is $1, the second $2.
Upvotes: 0