Reputation: 3
I have a line of text that I need to decrypt into a cipher text.
Let's say my line of text is abc def ghijklm n opq rstu vwx yz
and I want an output like this: aei qu c k rvzdhmptxbfjn y glosm
lets say I entered my "key" as 5. The code then will enter every 5th element of the array o f strings of the text from the text file.
This is the code I have come up with and I have hit a wall on what to do.
import java.io.*;
import java.util.*;
public class Files1 {
public static void main(String[] args) {
// TODO Auto-generated method stub
Scanner input = new Scanner(System.in);
int key;
System.out.print("Enter file: ");
String fileName = input.nextLine();
System.out.print("Please enter your Cipher Key: ");
key = input.nextInt();
Scanner inputStream = null;
System.out.println("File name is: " + fileName);
try {
inputStream = new Scanner(new File(fileName));
} catch (FileNotFoundException e) {
System.out.println("Error opening the file" + fileName);
System.exit(0);
}
while (inputStream.hasNextLine()) {
String text = inputStream.nextLine();
System.out.println(text);
char arrayText[] = text.toCharArray();
for (int i = 0; i < arrayText.length; i += key) {
System.out.print("\n" + arrayText[i]);
}
}
}
}
Here is whats happening in the console:
Enter file: abc.txt
File name is: abc.txt
abc def ghijklm n opq rstu vwx yz
a
e
i
q
u
Upvotes: 0
Views: 1995
Reputation: 3
import java.io.; import java.util.;
public class Files1 {
public static void main(String[] args) {
// TODO Auto-generated method stub
Scanner input = new Scanner(System.in);
int key;
System.out.print("Enter file: ");
String fileName = input.nextLine();
System.out.print("Please enter your Cipher Key: ");
key = input.nextInt();
Scanner inputStream = null;
System.out.println("File name is: " + fileName);
try {
inputStream = new Scanner(new File(fileName));
} catch (FileNotFoundException e) {
System.out.println("Error opening the file" + fileName);
System.exit(0);
}
while (inputStream.hasNextLine()) {
String text = inputStream.nextLine();
System.out.println(text);
for (int i = 0; i < text.length(); i++) {
System.out.print(text.charAt((i * key) % text.length()));
}
}
}
}
MANY THANKS TO EJP AND Pai!
i learned alot!
Upvotes: 0
Reputation: 310980
You don't specify what should happen to the spaces, or what happens when wraparound is required, but assuming spaces are significant and wrap-around just happens naturally:
for (int i = 0; i < text.length(); i++)
{
System.out.print(text.charAt((i*5) % text.length()));
}
prints aei qu c k rvzdhmptxbfjn y glosw
, which strongly suggests an error in your expected output.
Upvotes: 0
Reputation: 85
What you need is a circular list.
Here is a very simple and crude implementation of a circular list using arrays.
import java.util.Iterator;
import java.util.List;
public class CircularList implements Iterator<String> {
private String[] list;
private int pointerIndex;
private int key;
public CircularList(String[] list, int key) {
this.list = list;
pointerIndex = 1 - key;
this.key = key;
}
@Override
public boolean hasNext() {
if(list.length == 0){
return false;
}
return true;
}
@Override
public String next() {
if(pointerIndex + key > list.length) {
int diff = (list.length-1) - pointerIndex;
pointerIndex = key - diff;
return list[pointerIndex];
}else {
pointerIndex = pointerIndex + key;
return list[pointerIndex];
}
}
@Override
public void remove() {
//Do Nothing
}
}
Once you have a list in which you can iterate in a circular fashion, you can change you existing implementation to this -
import java.io.*;
import java.util.*;
public class Files1 {
public static void main(String[] args) {
System.out.print("Enter file: ");
Scanner input = new Scanner(System.in);
String fileName = input.nextLine();
Scanner inputStream = null;
System.out.println("" + fileName);
try {
inputStream = new Scanner(new File(fileName));
} catch (FileNotFoundException e) {
System.out.println("Error opening the file: " + fileName);
System.exit(0);
}
while (inputStream.hasNextLine()) {
String text = inputStream.nextLine();
System.out.println(text);
String[] splits = text.split("");
CircularList clist = new CircularList(splits, 5);
for (int i = 0; i < splits.length -1; i += 1) {
System.out.print("" + clist.next());
}
}
}
}
Output -
Enter file: resources\abc.txt
resources\abc.txt
abc def ghijklm n opq rstu vwx yz
aei qu c k rvzdhmptxbfjn y glosw
Also the last character in your cipher should be 'w' and not 'm'.
Upvotes: 1