CODEWITHSUNDEEP
python
user2041448
user2041448

Reputation: 91

remove certain consecutive duplicates in a string?

I want to define a function that takes a string and a letter in that string and outputs a new string with the occurrences of the letter being once. For example 

my_function("happy kitten","p")
'hapy kitten'

or 

my_function("happykitten","t") 
'happykiten'

I've tried 

def my_function(string, lett):
newString = ""
for char in string: #all characters
    for s in string: #character I'm testing
        if s == len(s) > 1: 
            newString+=lett # if there are multiple occurrences of s, replace with lett since its a single char anyway
        else:
            newString+=char #if not a duplicate, add next char to newString
    return newString #("happy kitten","p") returns 'ppppppppppp'

and 

def my_function(string, lett):
newString = ""
for char in string: #all characters
    for s in string: #character I'm testing
        if s == s+1: 
            newString+=lett # if there are multiple occurrences of s, replace with lett since its a single char anyway
        else:
            newString+=char #if not a duplicate, add next char to newString
    return newString #TypeError: cannot concatenate 'str' and 'int' objects

What't going wrong in my functions? Please no imports or built-in functions.

Upvotes: 3

Views: 2463

Answers (2)

ferrix
ferrix

Reputation: 761

Iterating over the characters is inefficient and most likely the wrong thing to do. Sounds really much like a homework assignment on a freshman course. In real life you should look into regular expressions and this question seems to provide an elegant answer.

Your problem is that you assume that s+1 points to the next value in the iterator and that is not a valid assumption. What you will have to do is record the sighting and on the next iteration act accordingly.

We can still solve this for the matter of practice:

def strip_duplicate_letters(input, letter):
  output = ''
  last = False

  for c in input:
    if c == letter:
      if last:
        continue
      else:
        last = True
    else:
      last = False
    output += c

  return output

This is such an elemental thing that you will have to think it thoroughly over to make sure you understand. Then forget the example and reproduce yourself.

Another way is to enumerate the letters to make index numbers available:

for i, c in enumerate(input):
  if i > 0 and c == letter and input[i-1] == letter:
    continue
  output += c

In case enumerate is too much of a problem, you can use an integer as counter and increment it.

i = 0
for c in input:
  ....
  i += 1
  ...

Upvotes: 2

arshajii
arshajii

Reputation: 129497

Well if you change your mind about the imports / built-in functions you can always do this:

from itertools import groupby

def my_function(s, c):
    return ''.join(c if a==c else ''.join(b) for a,b in groupby(s))

>>> from itertools import groupby
>>> def my_function(s, c):
...     return ''.join(c if a==c else ''.join(b) for a,b in groupby(s))
... 
>>> my_function("happy kitten","p")
'hapy kitten'
>>> my_function("happykitten","t")
'happykiten'

Upvotes: 4

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