CODEWITHSUNDEEP
c++-cli
Ken
Ken

Reputation: 33

How do I read multiple files after click opened in OpenFileDialog?

I have set a multiselect function in my code to allow me to open multiple files which is in ".txt" forms. And here is the problem, how am I going to read all these selected files after it opened through OpenFileDialog? The following codes and at the "for each" line, when I use System::Diagnostics::Debug, it shows only the data from a file, while data of other files were missing. How should I modify the code after the "for each"? Can anyone provide some suggestions or advice? The files selected are as 1_1.txt, 2_1.txt, 3_1.txt. Appreciate your reply and Thanks in advance.

Here is my written code,

Stream^ myStream;  
OpenFileDialog^ openFileDialog1 = gcnew OpenFileDialog;  
openFileDialog1->InitialDirectory = "c:\\";  
openFileDialog1->Title = "open captured file";  
openFileDialog1->Filter = "CP files (*.cp)|*.cp|All files (*.*)|*.*|txt files (*.txt)|*.txt";  
openFileDialog1->FilterIndex = 2;  
openFileDialog1->Multiselect = true;  

if ( openFileDialog1->ShowDialog() == System::Windows::Forms::DialogResult::OK )  
{  
  array<String^>^ lines = System::IO::File::ReadAllLines(openFileDialog1->FileName);  
  for each (String^ line in lines) {  
    //?????  
    System::Diagnostics::Debug::WriteLine("",line);  
  }  
}

Upvotes: 2

Views: 3015

Answers (3)

Agustin Meriles
Agustin Meriles

Reputation: 4854

Use openFileDialog1->FileNames. It returns the multiple filenames that you selected

Read here http://msdn.microsoft.com/en-us/library/system.windows.forms.openfiledialog.multiselect.aspx its in C# but, it will be easy to extrapolate to C++.

Upvotes: 0

Reed Copsey
Reed Copsey

Reputation: 564333

You need to look at the OpenFileDialog.FileNames property if you allow multiple files to be selected:

if ( openFileDialog1->ShowDialog() == System::Windows::Forms::DialogResult::OK )  
{  
  for each (String^ file in openFileDialog1->FileNames) 
  {  
    array<String^>^ lines = System::IO::File::ReadAllLines(file);  
    for each (String^ line in lines) 
    {  
      System::Diagnostics::Debug::WriteLine("",line);  
    }
  }  
}

Upvotes: 1

ken2k
ken2k

Reputation: 48975

Use the FileNames property.

C# version (should be easy to adapt for C++):

foreach (var file in openFileDialog1.FileNames)
{
    foreach (var line in File.ReadAllLines(file)
    {
    ...
    }
}

Upvotes: 0

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