Coffee Cup Drummer
Coffee Cup Drummer

Reputation: 15

Raphael.js onclick event

I am trying to make some simple buttons on Raphael.js. So I stuck in the last step. Here is my JSFiddle So my buttons keep the active state after you press them. But I trying to make pressed button inactive, when I press another.

I was trying to get st.node.state value with the loop inside the onclick function but it's just not working for me. Here is my code:

for(var i in aus) {

    (function (st) {

        st.node.state = 0;



        st.node.onmouseover = function() {
            st.animate({fill: "#8fbf27", stroke: "#fff"}, 100);
        };
        st.node.onmouseout = function() {
            st.animate({fill: "#555", stroke: "#fff"}, 100);
            if(this.state == 1){
                st.animate({fill: "#fff", stroke: "#fff"}, 100);
            }else {
                st.animate({fill: "#555", stroke: "#fff"}, 100);
            }
        };
        st.node.onclick = function() {

            if(this.state == 0) {
                this.state = 1;
                st.animate({fill: "#fff", stroke: "#fff"}, 100);
            }else {
                this.state = 0;
                st.animate({fill: "#555", stroke: "#fff"}, 100);
            }

        };

    })(aus[i]);

Upvotes: 0

Views: 3895

Answers (1)

numbers1311407
numbers1311407

Reputation: 34072

Something like this should work. This lets the elements animate themselves based on state. On click, if the element is being activated, loop through and deactivate the others.

// An animator function which will animate based on node state
var animate = function(st) {
  var fill = st.node.state ? "#fff" : "#555";
  st.animate({fill: fill, stroke: "#fff"}, 100);
}

for (i in aus) {
  (function (st) {
    st.node.state = 0;
    st.node.onmouseover = function () {
      if (!this.state) st.animate({fill: "#8fbf27", stroke: "#fff"}, 100);
    };
    st.node.onmouseout = function () {
      animate(st);
    };
    st.node.onclick = function () {
      this.state = 1 - this.state;
      animate(st);
      // if the node is deactivated stop now
      if (!this.state) return;
      // otherwise deactivate and animate the other nodes
      for (i in aus) {
        // if node is `this` or node is already deactivated, continue
        if (aus[i].node === this || !aus[i].node.state) continue;
        // otherwise deactivate and animate
        aus[i].node.state = 0;
        animate(aus[i]);
      }
    };
  }(aus[i]));
}

Alternatively, if only one is activated at a time, you might just store a reference to the one activated node and avoid looping.

// A reference to the active element
var activeEl;

// animate based on whether the st is the active element
var animate = function(st) {
  var fill = activeEl === st ? "#fff" : "#555";
  st.animate({fill: fill, stroke: "#fff"}, 100);
}

for (i in aus) {
  (function (st) {
    st.node.onmouseover = function () {
      if (!this.state) st.animate({fill: "#8fbf27", stroke: "#fff"}, 100);
    };
    st.node.onmouseout = function () {
      animate(st);
    };
    st.node.onclick = function () {
      if (!activeEl || activeEl !== st) {
        var el = activeEl;
        activeEl = st;
        if (el) animate(el);
      } else {
        activeEl = null;
      }
      animate(st);
    };
  }(aus[i]));
}

Upvotes: 3

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