masterofdestiny
masterofdestiny

Reputation: 2811

Passing an id in Django url

I want to pass userid from django url to my view

Here is what I have written in Django template

<a href ={% url 'user_details' x.id  %} class='btn btn-primary' style="float: right;" >Know More</a></div>

To handle this url I have written Url like

url(r'^User/(\d{userid})/$', 'search.views.user_detail',name='user_details'),     

But I am getting an error i.e

NoReverseMatch at /search/

Reverse for ''user_details'' with arguments '(2L,)' and keyword arguments '{}' not found.

Please help me out What might I am doing wrong here .

Upvotes: 12

Views: 48385

Answers (2)

Nuno Prata
Nuno Prata

Reputation: 358

Be carefull, after Django 1.5, use must use quotes. I came across this solution and tried it, got an error. I'm using Django 1.6 and you need the quotes:

<a href ={% url 'user_details' x.id  %} class='btn btn-primary' style="float: right;" >
    Know More
</a>

hope it helps.

Upvotes: 11

catherine
catherine

Reputation: 22808

No quote ''

<a href ={% url user_details x.id  %} class='btn btn-primary' style="float: right;" >
    Know More
</a>

Another your url

url(r'^User/(?P<userid>\d+)/$', 'search.views.user_detail', name='user_details'), 

Upvotes: 17

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