CODEWITHSUNDEEP
regexlua
flameiguana
flameiguana

Reputation: 35

Lua pattern matching, repeating character

I'm a beginner at pattern matching. I've learned that Lua's pattern matching is a little different from the standard, so I haven't been able to find a way to adapt regex solutions to this problem into Lua code.

I'm trying to replace the longest substring of a repeating character in a string.

For example, in abbbccccc, it would find a, bbb, ccccc.

This doesn't work, it just matches the whole string:

string.gsub(inputString, "(.+)", function (n) return replace(n) end)

I can see how why it wouldn't work, but I can't find another way.

I know I could solve this problem easily using a loop, but I'm trying to get more practice with regular expressions and such.

Thanks for helping.

Upvotes: 3

Views: 1738

Answers (1)

Egor Skriptunoff
Egor Skriptunoff

Reputation: 23737

It could not be done with a single pattern.
Use a pattern chain:

inputString:gsub('.','\0%0%0'):gsub('(.)%z%1','%1'):gsub('%z.(%Z+)',replace)

Upvotes: 1

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