CODEWITHSUNDEEP
jqueryfunctionpluginsmethods
ionescho
ionescho

Reputation: 1400

jquery plug-in inner workings

How come, if I define jQuery.fn.my_method = function(){...}, jQuery.my_method is not undefined even though I put my_method under the .fn property and not under jQuery directly?

I'm just curious.

 <script>
     jQuery.fn.my_method = function(){...};
     jQuery.my_method();//valid call even though i put my_method under .fn
 </script>

Upvotes: 0

Views: 37

Answers (1)

Daniel Imms
Daniel Imms

Reputation: 50149

jQuery.fn is an alias for jQuery.prototype, just like how $ is an alias for jQuery. What you're describing is perfectly normal, you're adding a method to the prototype which then becomes available on the object.

I suggest reading up on JavaScript prototypes.

Upvotes: 1

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