Reputation: 13
I'm trying to display information from a table in my database in a loop, but for certain information, I'm referencing other tables. When I try to get data from other tables, any data following will disappear. here is the code I am using:
`
//Below is the SQL query
$listing = mysql_query("SELECT * FROM Musicians");
//This is displaying the results of the SQL query
while($row = mysql_fetch_array($listing))
{
?>
...html here...
<? echo $row['name']; ?>
<? echo $row['Town']; ?>
<?
$CountyRef = $row['CountyId'];
$county = mysql_query("SELECT * FROM County WHERE CouInt='$CountyRef'");
while($row = mysql_fetch_array($county))
{
echo $row['CouName'];
}
?>
<?php echo $row['instrument']; ?>
<?php echo $row['style']; ?>`
My problem is that everything after the second while loop is not displaying. Anyone have any suggestions?
Thanks
Upvotes: 1
Views: 78
Reputation: 46900
Second loop should say $row2
. $row
is being overwritten. Both variables should be named different from each other.
Upvotes: 1
Reputation: 3098
And that?:
while($row2 = mysql_fetch_array($county)) {
echo $row2['CouName'];
}
Upvotes: 0
Reputation: 12305
You can acomplish that with a one single query:
SELECT *,
(SELECT CouName FROM County WHERE CouInt=mus.CountyId) as Country
FROM Musicians mus;
You final code should looks like:
<?php
$listing = mysql_query("SELECT *,
(SELECT CouName FROM County WHERE CouInt=mus.CountyId) as Country
FROM Musicians mus;");
//This is displaying the results of the SQL query
while($row = mysql_fetch_assoc($listing))
{
echo $row['name'];
echo $row['Town'];
echo $row['Country']; //Thats all folks xD
echo $row['instrument'];
echo $row['style'];
} ?>
Saludos ;)
Upvotes: 0