CODEWITHSUNDEEP
php
Marius Prollak
Marius Prollak

Reputation: 368

show php code in echo

How do I print php code in a print / echo ?

What I mean is this:

<?php echo "<?php ?>"; ?>

Should output: <?php ?> on my screen, but I receive a blank page. Any special escaping that I have to use ?

Upvotes: 4

Views: 1278

Answers (4)

SaidbakR
SaidbakR

Reputation: 13552

There is another solution built on str_replace which accepts arrays for its parameters search and replace.

<?php
 echo str_replace(array('<','>'),array('&lt;','&gt;'),'<?php ?>');
?>

Check out the following demo: http://phpfiddle.org/main/code/3hp-itx

Upvotes: 0

Jester
Jester

Reputation: 1303

If you print and you pretend to see it as HTML, the browser will interprete the tag and show nothing, but you will still be able to see it if you look at the source code. To show the < and > tags properly you should use &lt; and &gt; or use the htmlentities() or htmlspecialchars() functions:

<?php
  echo htmlentities( '<?php ?>' );
?>

Upvotes: 1

Luke Stevenson
Luke Stevenson

Reputation: 10351

Akam's solution sorts out the PHP, if the Content-Type of the returned file is HTML.

Alternately, you could change the Content-Type to Text, thereby bypassing the HTML rendering.

<?php

header( 'Content-type: text/plain' );

echo '<?php ?>';

?>

Of course, this would affect the whole page, and not just a segment of it. As such, it would be useful it you were displaying the contents of a PHP script file as a standalone page, but if you were wanting to show snippets of PHP code within an HTML page, then Akam's solution would be better suited for that.

Upvotes: 2

user1646111
user1646111

Reputation: 

<?php echo htmlspecialchars('<?php ?>'); ?>

Upvotes: 12

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