CODEWITHSUNDEEP
javaandroideclipse
LosTheAlef
LosTheAlef

Reputation: 25

Add an unknown number of Buttons programmatically

I wrote a simple app in which I want to add some buttons programmatically. The problem is that it is not sure how many buttons have to be added. I tried to put the "Button button = new Button" into a for-loop, because I thougt it only creates a local variable. I guess that's my fault ;)

This is my code:

public class MainActivity extends Activity {

LinearLayout auswahl;

String element [] = new String [10]; //This is just an example, it would take many pages to show how this array gets created.

@Override
protected void onCreate(Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);
    setContentView(R.layout.activity_main);

    auswahl = (LinearLayout)findViewById(R.id.LinearLayout2);

    element [1] = "A";
    element [2] = "B";
    element [3] = "C";
    element [4] = "D";
    element [5] = "E";
    element [6] = "F";
    element [7] = "G";
    element [8] = "H";
    element [9] = "I";
    element [0] = "J";

    int anzahl = element.length;

    for (int i = 0; i <= anzahl; i++){
        schreibeButtons(i, element[i]);
    }

}


public void schreibeButtons(int i, String string){

    Button button = new Button(this);

    button.setText(sortiment);
    button.setWidth(auswahl.getWidth());
    button.setHeight(40);
    button.setId(i*100);

    auswahl.addView(button);
} }

Are there any questions on what I want to reach? How to reach my aim?

Upvotes: 0

Views: 644

Answers (1)

Pragnani
Pragnani

Reputation: 20155

Mistake :

int anzahl = element.length;

Array of size n contains elements from 0 to n-1,

prasperK already pointed out that.

You are adding Every Button to your LinearLayout auswahl .

You can access your button from it only

Example : Number of Buttons - auswahl.getChildCount(); And you can access each button like this

To get button 1

Button button1=auswahl.getChildAt(0);

or simply by using ID

Button button1=(Button)auswahl.findViewById(101);

Upvotes: 1

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