CODEWITHSUNDEEP
pythonhttphttpsheaderurllib2
Stephane
Stephane

Reputation: 5078

Retrieve only HTTP response instead of debug info

I've the request below which works fine but it returns sent request and server full response. How can I just get response body ?

req = urllib2.Request('some url here', data = '')
opener = urllib2.build_opener(urllib2.HTTPSHandler(debuglevel = 1))
req = opener.open(req)
reply = req.read()
req.close()
print reply

Upvotes: 0

Views: 75

Answers (1)

phihag
phihag

Reputation: 287885

That extra information is explicitly requested with debuglevel=1. You can simply remove that, or even the whole opener definition, like this:

import urllib2
print (urllib2.urlopen('https://phihag.de/').read())

Upvotes: 1

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