CODEWITHSUNDEEP
pythonxmlparsingelementtree
Abhishek
Abhishek

Reputation: 1837

Parse all the xml files in a directory one by one using ElementTree

I'm parsing XML in python by ElementTree

import xml.etree.ElementTree as ET 
tree = ET.parse('try.xml')
root = tree.getroot()

I wish to parse all the 'xml' files in a given directory. The user should enter only the directory name and I should be able to loop through all the files in directory and parse them one by one. Can someone tell me the approach. I'm using Linux.

Upvotes: 18

Views: 35964

Answers (3)

Faheem
Faheem

Reputation: 1

def read_xml_files(input_folder, output_folder):

for root, dirs, files in os.walk(input_folder):
    for file in files:
        if file.endswith(".xml"):   
            file_path = os.path.join(root, file)
            dest_path = os.path.join(output_folder, file)
            shutil.copy(file_path, dest_path)
            print(f"Copied {file_path} to {dest_path}")

Upvotes: 0

Gaurang Kudale
Gaurang Kudale

Reputation: 1

import os
import xml.etree.ElementTree as ET

def parse_xml(xml_path):
    tree = ET.parse(xml_path)
    root = tree.getroot()
    classname = root.find('.//testcase').get('classname')
    time = float(root.get('time'))
    return classname, time

def main():
    data_folder = 'programming/assignment-1/data/'
    xml_files = [f for f in os.listdir(data_folder) if f.endswith('.xml')]

Upvotes: 0

Martijn Pieters
Martijn Pieters

Reputation: 1124788

Just create a loop over os.listdir():

import xml.etree.ElementTree as ET
import os

path = '/path/to/directory'
for filename in os.listdir(path):
    if not filename.endswith('.xml'): continue
    fullname = os.path.join(path, filename)
    tree = ET.parse(fullname)

Upvotes: 22

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