Reputation: 35239
Under OS X 10.8.3, have an environment like this:
$ bash --version
GNU bash, version 3.2.48(1)-release (x86_64-apple-darwin12)
Copyright (C) 2007 Free Software Foundation, Inc.
$ echo $PATH
/Users/r/Desktop/Beryl/usr/bin:/usr/local/mysql/bin:/usr/bin:/bin:/usr/sbin:/sbin:~/bin:/usr/local/bin:/usr/X11R6/bin
There are two copies of irb
in $PATH, as properly reported by which
:
$ which -a irb
/Users/r/Desktop/Beryl/usr/bin/irb
/usr/bin/irb
But when I run irb
I expect to get /Users/r/Desktop/Beryl/usr/bin/irb; instead I get /usr/bin/irb:
$ irb --version
irb 0.9.5(05/04/13) # this is the wrong version
$ /Users/r/Desktop/Beryl/usr/bin/irb --version
irb 0.9.6(09/06/30)
$ /usr/bin/irb --version
irb 0.9.5(05/04/13)
I don't have any aliases. I should mention that I launched bash by executing this script:
#!/bin/sh
export PATH=/Users/r/Desktop/Beryl/usr/bin:${PATH}
exec /bin/bash
Regardless, why is bash not running the first instance in $PATH?
Upvotes: 3
Views: 389
Reputation: 785876
Use following to determine from where irb is being executed:
type irb
To make bash shell to forget all remembered locations use:
hash -r
It appears that bash shell has previous location of irb
saved in an internal hash.
Check here fore details about hash in bash: http://linux.about.com/library/cmd/blcmdl1_hash.htm
Upvotes: 4
Reputation: 44424
It could be the hash that is causing the problem. When you first run a program it reads PATH
, but then bash
saves the location in an internal hash. It will use this hash subsequently (in the same session), regardless of the value of $PATH
.
List existing locations with the hash
command.
You can clear the hash with hash -r
.
Edit: see also the associative array BASH_CMDS
.
Upvotes: 2