CODEWITHSUNDEEP
rdfsparql
user2228191
user2228191

Reputation: 101

SPARQL Query: How I get only a literal or string as result?

Data:

<untitled-ontology-5:OperationName rdf:datatype="http://www.w3.org/2001/XMLSchema#string">
  Adhesive Curing
</untitled-ontology-5:OperationName>

SPARQL Query:

PREFIX rdf:<http://wwww.semanticweb.org/ontologies/2012/7/9/untitled-ontology-5#>
SELECT ?object
WHERE { ?subject  rdf:OperationName ?object .       
}

Result:

Adhesive Curing^^http://www.w3.org/2001/XMLSchema#string

My Question:

The result of the SPARQL Query is not the result what I wanted. The right result should contain only the Literal/String without the URI-part. I'd like to create the following result:

Proper Result:

Adhesive Curing

Upvotes: 9

Views: 11557

Answers (1)

Jeen Broekstra
Jeen Broekstra

Reputation: 22052

You need to use the STR() function to retrieve the lexical label of your literal:

Query: 

SELECT (str(?object) as ?label) 
WHERE { ?subject rdf:OperationName ?object . }

Upvotes: 17

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