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Cristiano
Cristiano

Reputation: 3189

How find the enum name for corresponding value and use it in DisplayFor?

I need to display the name of the enum for corresponding value inside DisplayFor HtmlHelper. I have the following enum:

public enum CheckStatus
    {
        Yes = 1,
        No = 2,
        Maybe =3
    }

I'm displaying values for a model normally like this:

@Html.DisplayFor(modelItem => item.Name)

The problem is that at one point I have this:

@Html.DisplayFor(modelItem => item.Status)

That line displays only status value which is set before from enum (1,2 or 3). Instead of that I need somehow to display name for that value. So, if status code is 2, I want to display 'No', not number 2.

I had the similar problem with getting enum names when I was populating dropdown list and I managed to solve it like this:

@Html.DropDownListFor(model => model.Item.Status,
                new SelectList(Enum.GetValues(typeof(Pro.Web.Models.Enums.CheckStatus))))

I am a little bit lost in how to get only that one name from the value of the enum.

Thank you for your help.

Upvotes: 5

Views: 8073

Answers (4)

Patrick R
Patrick R

Reputation: 31

using razor/MVC you can get this for "free" if your property in not declared as an int type but rather as the enum type yoou are using.

The problem I have with Darin solution is although it works for me if I use the int type, I could not get the look of my other fields @Html.EditorFor(...) in the view.

Upvotes: 1

lxa
lxa

Reputation: 3332

Adapted @DarinDimitrov code as display template.

If you have 

public enum CheckStatus
{
    [Display(Name = "oh yeah")]
    Yes = 1,
    [Display(Name = "no, no, no...")]
    No = 2,
    [Display(Name = "well, dunno")]
    Maybe = 3
}

public class MyModel
{
    public CheckStatus Status { get; set; }
}

put following into Views/DisplayTemplates/Enum.cshtml :

@using System.ComponentModel.DataAnnotations
@model object

@{
    var value = Model.ToString();
    var field = Model.GetType().GetField(value);
    if (field != null)
    {
        var displayAttribute = field
                .GetCustomAttributes(typeof(DisplayAttribute), false)
                .Cast<DisplayAttribute>()
                .FirstOrDefault();

        if (displayAttribute != null)
        {
            value = displayAttribute.GetName();
        }
    }
}

@value

and now you can simply write in your view:

@Html.DisplayFor(model => model.Status)

Upvotes: 1

Ramesh Rajendran
Ramesh Rajendran

Reputation: 38683

Edit:

You can simply try this way. please try my below code in your controller class

controller:

int enumvalue=(int)(YourModel.Status)// this property must be integer value only
var checkStatusName= Enum.GetName(typeof(CheckStatus), enumvalue);

Upvotes: 3

Darin Dimitrov
Darin Dimitrov

Reputation: 1038790

It's not very clear from your question what's the underlying type of the Status property. If it is CheckStatus, then @Html.DisplayFor(modelItem => item.Status) will display exactly what you expect. If on the other hand it is an integer you could write a custom helper to display the proper value:

public static class HtmlExtensions
{
    public static IHtmlString DisplayEnumFor<TModel>(this HtmlHelper<TModel> html, Expression<Func<TModel, int>> ex, Type enumType)
    {
        var value = (int)ModelMetadata.FromLambdaExpression(ex, html.ViewData).Model;
        string enumValue = Enum.GetName(enumType, value);
        return new HtmlString(html.Encode(enumValue));
    }
}

and then use it like this:

@Html.DisplayEnumFor(modelItem => item.Status, typeof(CheckStatus))

and let's suppose that you wanted to bring this helper a step further and take into account the DisplayName attribute on your enum type:

public enum CheckStatus
{
    [Display(Name = "oh yeah")]
    Yes = 1,
    [Display(Name = "no, no, no...")]
    No = 2,
    [Display(Name = "well, dunno")]
    Maybe = 3
}

Here's how you could extend our custom helper:

public static class HtmlExtensions
{
    public static IHtmlString DisplayEnumFor<TModel>(this HtmlHelper<TModel> html, Expression<Func<TModel, int>> ex, Type enumType)
    {
        var value = (int)ModelMetadata.FromLambdaExpression(ex, html.ViewData).Model;
        string enumValue = Enum.GetName(enumType, value);
        var field = enumType.GetField(enumValue);
        if (field != null)
        {
            var displayAttribute = field
                .GetCustomAttributes(typeof(DisplayAttribute), false)
                .Cast<DisplayAttribute>()
                .FirstOrDefault();
            if (displayAttribute != null)
            {
                return new HtmlString(html.Encode(displayAttribute.Name));
            }
        }
        return new HtmlString(html.Encode(enumValue));
    }
}

Upvotes: 7

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