CODEWITHSUNDEEP
android
AnRu
AnRu

Reputation: 67

android using an image several times

enter image description here[the green and red images should be in linear and must be displayed wit respective to the value in dotColors[]. ]

@Override
  public View getView(int position, View convertView, ViewGroup parent) {
  View v = super.getView(position, convertView, parent);
  dotColors = datasource.getColorsArrayForWeek(tasks.get(position).getId(), call.get(Calendar.DAY_OF_YEAR));    
  LinearLayout tlli = (LinearLayout)v;
  jj=0;



jj=0; 
   while(jj<7)
   {
       if(dotColors[jj]==0)
       {
            red=(ImageView) tlli.findViewById(R.id.day1);
        }
        else if(dotColors[jj]==1)
        {
            green=(ImageView) tlli.findViewById(R.id.day2);

        }
        jj++;
        Log.i("jj::" +jj," ");
    }
    return v;
    }

after querying from the database the values are stored in dotColors[]. dotColors[] contains integer elements whose values are only 0 and 1.. If the value is 0 I have to display "red" image, if its 1 I have to display "green" image. how can I achieve it? Hope the explanation is much more clear now wid the image

Upvotes: 2

Views: 87

Answers (4)

user1526671
user1526671

Reputation: 817

In your Layout set both image view visibility as android:visibility = "GONE" In your oncreate method

    red=(ImageView) tlli.findViewById(R.id.day1);
    green=(ImageView) tlli.findViewById(R.id.day2);

in condition

   if(dotColors[jj]==0)
   {
        red.setVisibility(View.Visible);
        red.setBackgroundResource(R.drawable.imageName)
        //if ur image in folder res/drawable
    }
    else if(dotColors[jj]==1)
    {
        green.setVisibility(View.Visible);
        green.setBackgroundResource(R.drawable.imageName1)

    }

Upvotes: 1

Chirag Patel
Chirag Patel

Reputation: 11508

Is this that you want

@Override
  public View getView(int position, View convertView, ViewGroup parent) {
  View v = super.getView(position, convertView, parent);
  dotColors = datasource.getColorsArrayForWeek(tasks.get(position).getId(), call.get(Calendar.DAY_OF_YEAR));    
  LinearLayout tlli = (LinearLayout)v;
  jj=0;
   while(jj<7)
   {
       if(dotColors[jj]==0)
       {
            red=(ImageView) tlli.findViewById(R.id.day1);
            red.setImageResource(R.drawable.redImage);
        }
        else if(dotColors[jj]==1)
        {
            green=(ImageView) tlli.findViewById(R.id.day1);
            green.setImageResource(R.drawable.greenImage);

        }
        jj++;
        Log.i("jj::" +jj," ");
    }
    return v;
    }

Upvotes: 0

Rahul
Rahul

Reputation: 45060

I think you want to be able to see the color changes. Your code executes so fast, that the changes are not visible and it directly lands up with the case where jj=76. Add a Thread.sleep(millis) in your code, to be able to see the changes.

jj = 0;
while (jj < 77) {
    if(dotColors[jj]==0) {
        // Do your red thingy.
    } else {
        // Do your green thingy.
    }
    try {
        Thread.sleep(2000); // every 2 secs, you can see the change. Change as per your need
    } catch (InterruptedException e) {
        //Exception handling
    }
    Log.i("jj::" +jj," ");
    jj++;
}

Upvotes: 0

Viswanath Lekshmanan
Viswanath Lekshmanan

Reputation: 10083

red=(ImageView)findViewById(R.id.yourimageviewid);

green=(ImageView)findViewById(R.id.yourimageviewid);

put this in oncreate()

use setImageBitmap() to setimages dynamically

Upvotes: 0

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