Reputation: 3
my question has to do with the pods framework plugin for wordpress sites. I am using pods version 2.2 and have been having trouble with the where parameter in the find() function.
I'd be suprised if I am the first person to encounter this problem but I have searched extensively and haven't found anyone providing an answer (or question at that).
Anyway, I'll give an example to highlight my problem.
Say I have a Bands Pod and a Records Pod and these two pods have a bi-directional multi-select relationship between them (that is, an n to n relationship). Hence a band can have numerous records and a record can have multiple bands. Further, the relationship exists between the fields BandsPod('records') and RecordsPod('bands').
Now, I can retrieve all records in the records pod like so (note the where is commented out):
$pods = pods('records');
$params = array(
'select' => 't.*',
'limit' => -1
//,'where' => '???'
);
$pods->find($params);
Then do whatever I want with them, e.g. template(), fetch(), etc.
My trouble occurs when I want to filter by band. What should my where statement be if I want to retrieve all records by band with id 1?
My view is that it should be something like this:
$params = array(
'select' => 't.*',
'limit' => -1,
'where' => '1 IN bands.id'
);
$pods->find($params);
However, this does not work (not that I especially expected it to).
It would also be desirable to know how this would work for filtering by multiple bands. E.g.
'where' => '(1, 2) IN bands.id'
As I said before, I've been trying to get this to work for some time and with little joy. I have managed to get it working but in a very ugly way. I.e.
Thanks in advance for taking the time to read this and any answers you may give.
Cheers, Joe
N.B. I know about the filters() function and it does not do what I'm after. I'd like stuff specifically for the where statement please.
Upvotes: 0
Views: 3146
Reputation: 987
You would want:
'where' => 'bands.id IN ( 1, 2 )'
If your bands are a custom post type, it would be:
'where' => 'bands.ID IN ( 1, 2 )'
Upvotes: 0