CODEWITHSUNDEEP
c#xml
Kirill
Kirill

Reputation: 37

XML reading string value between tags

Suppose, I have the follwing XML:

    <SplitterLayoutDataSet xmlns="http://tempuri.org/SplitterLayoutDataSet.xsd"> 
        <SplitterLayout> 
            <SplitterName>mainSplitContainerControl</SplitterName>
            <SplitterPosition>0.2213375796178344</SplitterPosition>
        </SplitterLayout> 
    </SplitterLayoutDataSet>

I need a way how to get SplitterPosition value, in this case: 0.2213375796178344. Is there any receipt to reach this solution without using Linq-to-XML, or letting combine these ways? This XML is designed in SplitterLayoutDataset.xsd file. Or how do I read the field SplitterPosition of that file directly with C# tools? Thanks

Upvotes: 1

Views: 905

Answers (1)

rsbarro
rsbarro

Reputation: 27349

Here's a solution using XmlDocument and SelectSingleNode:

var xml = @"
<SplitterLayoutDataSet xmlns=""http://tempuri.org/SplitterLayoutDataSet.xsd""> 
   <SplitterLayout> 
       <SplitterName>mainSplitContainerControl</SplitterName>
       <SplitterPosition>0.2213375796178344</SplitterPosition>
   </SplitterLayout> 
</SplitterLayoutDataSet>";

//Create XmlDocument
var xmlDoc = new XmlDocument();
xmlDoc.LoadXml(xml);

//Create NamespaceManager (for XPath)
var nsMgr = new XmlNamespaceManager(xmlDoc.NameTable);
nsMgr.AddNamespace("dn", "http://tempuri.org/SplitterLayoutDataSet.xsd");

//Get inner text of SplitterLayout/SplitterPosition
var xPath = "//dn:SplitterLayout/dn:SplitterPosition";
Console.WriteLine(xmlDoc.SelectSingleNode(xPath, nsMgr).InnerText);

Or based on @AlexeiLevenkov's suggestion, you could eliminate the NamespaceManager by using the following XPath:

var xPath = "//*[local-name()='SplitterPosition']";
Console.WriteLine(xmlDoc.SelectSingleNode(xPath).InnerText);

Of course, you can also use XDocument:

var xdoc = XDocument.Parse(xml);
XNamespace ns = @"http://tempuri.org/SplitterLayoutDataSet.xsd";
Console.WriteLine(xdoc.Descendants(ns + "SplitterPosition").First().Value);

Or using XDocument and XPathSelectElement:

var xdoc = XDocument.Parse(xml);
var xPath = "//*[local-name()='SplitterPosition']";
Console.WriteLine(xdoc.XPathSelectElement(xPath).Value);

Upvotes: 2

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