CODEWITHSUNDEEP
javaswingcardlayout
Ren
Ren

Reputation: 4683

CardLayout to close on last card

So I have a JPanel with a CardLayout. this CardLayout, as expected, manages the switching of panels in the frame. The switching is done by two buttons: "Back" and "Next".

I want to know if there is a way to close the whole application (i.e. call System.exit(0)) when it is on the last card and "Next" is pressed again.

I have looked for a solution everywhere, but I can't find anything.

The problem is: I don't know how to check which is the last one.

Here is the listener excerpt of my code:

public void actionPerformed(ActionEvent arg0) {
        CardLayout l = (CardLayout) holder.getLayout();
        if(arg0.getSource() == opt[1]){ //opt[1] is the "Next" button


                //Insert if statement here to check if
                //the CardLayout is on the last card
                {
                System.exit(0);
                } else {
                    l.next(holder); //holder is the JPanel with the CardLayout
                }
        }
}

Upvotes: 0

Views: 973

Answers (4)

camickr
camickr

Reputation: 324128

I extended CardLayout to add a few features. One of the features is an isNextCardAvailable() method. See Card Layout Focus for all the features.

Upvotes: 3

Eng.Fouad
Eng.Fouad

Reputation: 117597

What about dispose() which is inherited from Window? Make sure you set:

jframe.setDefaultCloseOperation(JFrame.EXIT_ON_CLOSE);


JFrame frame = ...

// ...

frame.setVisible(false); // hide the GUI
frame.dispose(); // destroy and release the GUI resources

For example:

enter image description here

import java.awt.BorderLayout;
import java.awt.CardLayout;
import java.awt.event.ActionEvent;
import java.awt.event.ActionListener;

import javax.swing.BorderFactory;
import javax.swing.JButton;
import javax.swing.JFrame;
import javax.swing.JLabel;
import javax.swing.JPanel;

public class CardLayoutGUI
{
    private JFrame frame;
    private JButton btnBack;
    private JButton btnNext;
    private CardLayout cLayout;
    private JPanel panUp;
    private JPanel panDown;

    private static final String[] cards =
    {"card1", "card2", "card3", "card4", "card5"}; 

    private int currentCard = 0;

    public void init()
    {
        frame = new JFrame();
        frame.setDefaultCloseOperation(JFrame.EXIT_ON_CLOSE);
        ((JPanel)frame.getContentPane()).setBorder(BorderFactory.createEmptyBorder(5, 5, 5, 5));

        btnBack = new JButton("Back");
        btnNext = new JButton("Next");

        btnBack.addActionListener(new ActionListener()
        {
            @Override
            public void actionPerformed(ActionEvent e)
            {
                btnNext.setText("Next");
                currentCard--;
                cLayout.show(panUp, cards[currentCard]);
                if(currentCard == 0) btnBack.setVisible(false);
            }
        });

        btnNext.addActionListener(new ActionListener()
        {
            @Override
            public void actionPerformed(ActionEvent e)
            {
                btnBack.setVisible(true);
                currentCard++;

                if(currentCard == cards.length - 1) // last card
                {
                    btnNext.setText("Exit");
                    cLayout.show(panUp, cards[currentCard]);
                }
                else if(currentCard >= cards.length)
                {
                    frame.setVisible(false);
                    frame.dispose();
                }
                else
                {
                    cLayout.show(panUp, cards[currentCard]);
                }
            }
        });


        cLayout = new CardLayout();
        panUp = new JPanel(cLayout);
        panDown = new JPanel();
        frame.add(panUp, BorderLayout.CENTER);
        frame.add(panDown, BorderLayout.SOUTH);
        panDown.add(btnBack);
        panDown.add(btnNext);

        for(int i = 0; i < cards.length; i++) createPanels(panUp, cards[i]);

        frame.pack();
        frame.setLocationRelativeTo(null);

        btnBack.setVisible(false);
    }

    public void showGUI()
    {
        frame.setVisible(true);
    }

    private void createPanels(JPanel container, String label)
    {
        JPanel pan = new JPanel();
        pan.add(new JLabel(label));
        container.add(pan, label);
    }

    public static void main(String[] args)
    {
        SwingUtilities.invokeLater(new Runnable()
        {
            @Override
            public void run()
            {
                CardLayoutGUI clg = new CardLayoutGUI();
                clg.init();
                clg.showGUI();
            }
        });
    }
}

Upvotes: 3

Reimeus
Reimeus

Reputation: 159784

The issue is determining which card is the last one. You could use a card String array index to manage the current position of the and use the show method to display the next "card". When you exceed the card array index you can then dispose your JFrame.

Upvotes: 2

JorgeLoya
JorgeLoya

Reputation: 1

If you run the System.exit(0), that close all aplication, but if you only close the JFrame you can use JFrameObject.dispose().

Upvotes: 0

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