CODEWITHSUNDEEP
c++
Ylli F
Ylli F

Reputation: 17

Output shows no zero

FYI I'm a beginner in C++. This is just a part of the complete code, the problem is the 'student.id', if the input starts with '0' e.g.'06042010', the output shows no zero(in this case would be '6042010'! And the point is, I want that first zero to be shown. Thanks.

#include<iostream>
using namespace std;

struct students
{
    char name[15];
    char surname[10];
    int id;

};

int main()
{
    students student;

cout<<"Name: ";
cin>>student.name;
cout<<"Surname: ";
cin>>student.surname;
cout<<"ID: ";
cin>>student.id;

cout<<"\nStudent: "<<student.name<<" "<<student.surname<<" ID "<<student.id<<endl;

return 0;

}

Upvotes: 1

Views: 118

Answers (3)

Edward Goodson
Edward Goodson

Reputation: 302

If you need or want to keep the student id a number for some reason you can also us the following: 

#include <iomanip>

const int width = 8; //The length of your student ID numbers

cout << "\nStudent: " << student.name << " " <<student.surname
     << " ID " << setfill('0') << setw(width) << student.id << setfill(' ') << endl;

If your ID numbers are not all the same length you will have to detect how long they are and use the appropriate width in each setw() call.

Upvotes: 0

Dave
Dave

Reputation: 46259

If your IDs will always be a particular length, you can use C's printf function instead of streams, which gives you more power;

printf( "Student: %s %s ID %08d\n", student.name, student.surname, student.id );

That will always print 8 digits of ID, and will prefix with 0s as needed (if it was just %8d it would prefix with spaces).

But as already pointed out, you're likely better off storing it as a string, because then you will be able to increase the length of the IDs in the future without needing to adjust all the old IDs.

Upvotes: 1

NPE
NPE

Reputation: 500377

If you need to preserve leading zeros, you should store id as a string and not an int.

Upvotes: 5

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