CODEWITHSUNDEEP
c++arrayspointerscharbyte
user2012481
user2012481

Reputation: 9

Pointers & converting a char array to an int

I am doing some exercises to figure out how to access values in an array after they are changed with pointers. Can someone point out why the first output does not show the desired output? I am trying to get both cout to print 1234, one by using the new pointer and one by using the position in the array

int main()
{
    char myArray[50]={0};
    short* sizeOfAlloc=(short*)(myArray+5);  
         *sizeOfAlloc=1234;

    cout << (short*)(myArray+5) <<endl; 
    cout << *sizeOfAlloc <<endl;
    system("pause");

}

Upvotes: 0

Views: 614

Answers (1)

user995502
user995502

Reputation: 

cout << (short*)(myArray+5) <<endl;

Prints the pointer. Not the value pointed by it.

cout << *((short*)(myArray+5)) <<endl;
        ^^                   ^^

Will print the value pointed to by (short*)(myArray+5)

Upvotes: 2

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