CODEWITHSUNDEEP
ruby-on-railsrubyruby-on-rails-3
Ganesh Kunwar
Ganesh Kunwar

Reputation: 2653

Find month names for the last year

In my ruby code I want to display all the months name of last 1 year. For example current date is "April 2013" then I want to display all months name from "May 2012" to "April 2013" such as ["May", "June", .., "April"]. What is the best idea for this?

I tried: 

<%= (1.year.ago.to_date.strftime("%B")..Date.today.strftime("%B")).map %> { |a| a } %>

But it gives: ["April"].

Upvotes: 3

Views: 1529

Answers (5)

Mischa
Mischa

Reputation: 43298

In Rails you can do something like this:

<% 11.downto(0) do |i| %>
  <%= i.months.ago.strftime("%­B %Y") %>
<% end %>

Upvotes: 7

Aleksei Matiushkin
Aleksei Matiushkin

Reputation: 121000

Just out of curiosity, there is not wide-known nifty shift operator on Date:

(-12..0).inject([]) { 
  |agg, v| agg << Date::MONTHNAMES[(Date.today << v).month] 
}

or, even simplier:

(-12..0).map { |v| Date::MONTHNAMES[(Date.today << v).month] }

Upvotes: 3

shime
shime

Reputation: 9008

(0..11).map do |month|
    (11.months.ago + month.months).strftime("%B %Y")
end

Upvotes: 3

tokland
tokland

Reputation: 67850

11.downto(0).map { |m| m.months.ago.strftime("%B %Y") }
#=> ["May 2012", "June 2012", ..., "March 2013", "April 2013"]

Upvotes: 5

mrks
mrks

Reputation: 8333

Try this:

(0..11).each { |i|
  month = (Date.today.month + i) % 12 + 1;
  puts Date.new(Date.today.year - 1 + (month < Date.today.month ? 0 : 1), month).strftime("%B %Y")
}

Upvotes: 1

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