CODEWITHSUNDEEP
groovy
Avinash
Avinash

Reputation: 347

Groovy Expression evaluation

A basic groovy question. In order to make my code robust, I need to make use of Eval.me(String) that groovy offers.

I have a problem though.It arises when I try to do string comparison.

def x='yay'
def y='yay'
def groovyString="'$x' == '$y'"
println Eval.me(groovyString);

This prints true.

But the below code just says 'yay' is not a variable definition,

def x='yay'
def y='yay'
def groovyString="$x == $y"
println Eval.me(groovyString);

I am aware as to why this error is coming :) Is there a way where i can sidestep this issue w/o actually needing to append ' ' for string comparisions??

P.S:I need it to work properly for more than just strings. Hence the apprehension to append ' '

Upvotes: 4

Views: 1955

Answers (1)

tim_yates
tim_yates

Reputation: 171194

You should be able to do this with a Binding and GroovyShell

If we make an instance of GroovyShell with a Binding that by default returns the name of the property when no property s found:

def shell = new GroovyShell( new Binding( [:].withDefault{ it } ) )

We can then evaluate your groovyString:

shell.evaluate( groovyString )

Which basically evaluates to the first form, as both yay properties get resolved to the String yay

Upvotes: 2

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