CODEWITHSUNDEEP
phpregexpreg-replaceline-breakscarriage-return
Andre Chenier
Andre Chenier

Reputation: 1186

php regex - remove \r\n\r\n at the very beginning AND at the very end in a string

If exists, I need to remove \r\n\r\n at the very beginning and/or at the very end of string.

My issue is I couldn't achieve my aim with codes below.

//if exists, remove \r\n\r\n at the very beginning
$str = preg_replace('/^(\r\n\r\n)/', '', $str);

//if exists, remove \r\n\r\n at the very end
$str = preg_replace('/$(\r\n\r\n)/', '', $str);

maybe my html output's source view can give some clues to you. I don't know the reason but <br /> tags are not side-by-side. They position as one-under-the-other.

<br />
<br />
some text
...
...
some text<br />
<br />

Also below, I share my whole string manipulation code. My problematic 2 rows of code is a part of the code below. (The other parts except 2 rows of code above works well)

function convert_str ($str)
{
    // remove excess whitespace
    // looks for a one or more spaces and replaces them all with a single space.
    $str = preg_replace('/ +/', ' ', $str);
    // check for instances of more than two line breaks in a row
    // and then change them to a total of two line breaks
    $str = preg_replace('/(?:(?:\r\n|\r|\n)\s*){2}/s', "\r\n\r\n", $str);
    //if exists, remove \r\n\r\n at the very beginning
    $str = preg_replace('/^(\r\n\r\n)/', '', $str);

    //if exists, remove \r\n\r\n at the very end
    $str = preg_replace('/$(\r\n\r\n)/', '', $str);

    //if exists, remove 1 space character just before any  \r\n
    $str = str_replace(" \r\n", "\r\n", $str);
    //if exists, remove 1 space character just after any \r\n
    $str = str_replace("\r\n ", "\r\n", $str);  
    // if exists; remove 1 space character just before punctuations below:
    // $punc = array('.',',',';',':','...','?','!','-','—','/','\\','“','”','‘','’','"','\'','(',')','[',']','’','{','}','*','&','#','^','<','>','|');
    $punc = array(' .',' ,',' ;',' :',' ...',' ?',' !',' -',' —',' /',' \\',' “',' ”',' ‘',' ’',' "',' \'',' (',' )',' [',' ]',' ’',' {',' }',' *',' &',' #',' ^',' <',' >',' |');
    $replace = array('.',',',';',':','...','?','!','-','—','/','\\','“','”','‘','’','"','\'','(',')','[',']','’','{','}','*','&','#','^','<','>','|');
    $str = str_replace($punc,$replace,$str);
    return $str;
}

Can you please correct me?

Thanks

BR

Upvotes: 1

Views: 5930

Answers (2)

Abela
Abela

Reputation: 1233

You will want to use the trim() string function to handle this.

trim — Strip whitespace (or other characters) from the beginning and end of a string

Example:

$str = trim($str);

Upvotes: 2

Pouki
Pouki

Reputation: 1664

Try to replace 

//if exists, remove \r\n\r\n at the very end
$str = preg_replace('/$(\r\n\r\n)/', '', $str);

by 

//if exists, remove \r\n\r\n at the very end
$str = preg_replace('/(\r\n\r\n)$/', '', $str);

You can also try to use the Trim function (e.g. string trim ( string $str [, string $charlist = " \t\n\r\0\x0B" ] ) )

Upvotes: 0

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