CODEWITHSUNDEEP
javaregex
Max Usanin
Max Usanin

Reputation: 2499

verification of compliance (Regex)

my source

Matcher matcher = Pattern.compile("[0-9]").matcher("35423523");

matcher.matches() - now is false

but I need to matcher.matches() - true - because the string is all numbers

or for example

Pattern.compile("[0-9A-Za-z]").matcher("35dwedwfeASADdfd423523"); - must be true

or Pattern.compile("[0-9]").matcher("354ccwq23523"); - must be false or Pattern.compile("[0-9a-z]").matcher("354ccwq23523"); - must be true

how to do that ?

Upvotes: 1

Views: 186

Answers (3)

Oliver Atkinson
Oliver Atkinson

Reputation: 8029

Pattern.compile("[0-9]+").matcher("35423523");

TRUE

Pattern.compile("[0-9A-Za-z]+").matcher("35dwedwfeASADdfd423523");

TRUE

Pattern.compile("[0-9]+").matcher("354ccwq23523");

FALSE

Pattern.compile("[0-9a-z]+").matcher("354ccwq23523");

TRUE

If you want to match certain lengths you could use [0-9]{1, 4} (lower limit -> upper limit)

Upvotes: 2

Jon Lin
Jon Lin

Reputation: 143906

The matches() method checks the entire region against the pattern. That means your pattern needs to match the entire String:

Matcher matcher = Pattern.compile("[0-9]+").matcher("35423523");

and

Pattern.compile("[0-9A-Za-z]+").matcher("35dwedwfeASADdfd423523");

From the javadocs:

Returns true: if, and only if, the entire region sequence matches this matcher's pattern

Upvotes: 2

errieman
errieman

Reputation: 1949

Your regex says that the string can only be one character wide, if you want more you should use repetition. Then it would look like this: [0-9]+ or [0-9A-Za-z]+.

Upvotes: 5

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