Reputation: 748
As mentioned here you can use reference (d-reference) instead of pointer (d-pointer) in case of PIMPL idiom.
I'm trying to understand if there are any serious issues with this implementation and what are the pros and cons.
Pros:
Cons:
if (m_Private)
m_Private->Foo();
Here the sample code for illustration:
// Header file
class ObjectPrivate;
class Object
{
public:
Object();
virtual ~Object();
virtual void Foo();
private:
ObjectPrivate& m_Private;
};
// Cpp file
class ObjectPrivate
{
public:
void Boo() { std::cout << "boo" << std::endl; }
};
Object::Object() :
m_Private(* new ObjectPrivate())
{
}
Object::~Object()
{
delete &m_Private;
}
void Object::Foo()
{
m_Private.Boo();
}
Upvotes: 4
Views: 2583
Reputation: 104698
Some quick and obvious additions:
Pro
0
.Con
Upvotes: 1
Reputation: 659
It's not convenient to write exception-safe code I think.
The first version of Object::operator=(Object const&)
might be:
Object& operator=(Object const& other)
{
ObjectPrivate *p = &m_Private;
m_Private = other.m_Private; // Dangerous sometimes
delete *p;
}
It's dangerous if ObjectPrivate::operator=(ObjectPrivate const&)
throws exception. Then what about using a temporary variable? Aha, no way. operator=()
has to be invoked if you want change m_Private.
So, void ObjectPrivate::swap(ObjectPrivate&) noexcept
can act as our savior.
Object& operator=(Object const& other)
{
ObjectPrivate *tmp = new ObjectPrivate(other.m_Private);
m_Private.swap(*tmp); // Well, no exception.
delete tmp;
}
Then consider the implementation of void ObjectPrivate::swap(ObjectPrivate&) noexcept
. Let's assume that ObjectPrivate might contain a class instance without swap() noexcept
or operator=() noexcept
. I think it's hard.
Alright then, this assumption is too strict and not correct sometimes. Even so, it's not necessary for ObjectPrivate to provide swap() noexcept
in most cases, because it's usually a helper structure to centralize data.
By contrast, pointer can save a lot of brain cells.
Object& operator=(Object const& other)
{
ObjectPrivate *tmp = new ObjectPrivate(*other.p_Private);
delete p_Private;
p_Private = tmp; // noexcept ensured
}
It's much more elegant if smart pointers are used.
Object& operator=(Object const& other)
{
p_Private.reset(new ObjectPrivate(*other.p_Private));
}
Upvotes: 1
Reputation: 153909
It's really just a matter of style. I tend to not use
references in classes to begin with, so using a pointer in the
compilation firewall just seems more natural. But there's
usually no real advantage one way or the other: the new
can
only fail by means of an exception.
The one case where you might favor the pointer is when the
object has a lot of different constructors, some of which need
preliminary calculations before calling the new
. In this
case, you can initialize the pointer with NULL
, and then call
a common initialization routine. I think such cases are rare,
however. (I've encountered it once, that I can recall.)
EDIT:
Just another style consideration: a lot of people don't like something like delete &something;
, which is needed if you use references rather than pointers. Again, it just seems more natural (to me, at least), that objects managing memory use pointers.
Upvotes: 6