CODEWITHSUNDEEP
javarandom
Strobe_
Strobe_

Reputation: 515

How to generate a random object?

Ok, so I have been tasked with creating a number of robots that find their way out of a situation. i.e There is a hole in the wall and they have to find the way out no matter where they spawn.

I have created a loop that makes 10 different robots but they all spawn on the same place:

EscapeBot[] Karel = new EscapeBot[numOfRobots];

for (int i = 0; i < numOfRobots; i++) {
    Karel[i] = new EscapeBot(London, 1, 1, Direction.NORTH);
    Karel[i].escapeRoom();

Should I be declaring integers and then using math.random within the for loop where the co-ordinates and direction are?

Upvotes: 2

Views: 2961

Answers (2)

Marckvdv
Marckvdv

Reputation: 159

How about doing it like this(If you want to let robot to be able to spawn annywhere, just replace the spawn variables with your map dimensions): 

for (int i = 0; i < numOfRobots; i++) {
                Karel[i] = new EscapeBot(London, 
                SPAWN_X + SPAWN_LENGTH * Math.random(), 
                SPAWN_Y + SPAWN_WIDTH * Math.random(), 
                Direction.NORTH);

                Karel[i].escapeRoom();
}

Upvotes: 1

Zim-Zam O&#39;Pootertoot
Zim-Zam O&#39;Pootertoot

Reputation: 18148

I can't say for certain without seeing your EscapeBot class, but that's probably want you want, e.g.

Random rand = new Random();
new EscapeBot(London, rand.nextInt(max_x - 1) + 1, rand.nextInt(max_y - 1) + 1, Direction.NORTH);

where max_x is the maximum x-coordinate and max_y is the maximum y-coordinate, assuming 1-based indexing (if using 0-based indexing then remove the -1 and +1 parts). You may also want an array of directions, e.g.

Direction[] directions = new Direction { Direction.NORTH, Direction.SOUTH, .. }

so that your EscapeBot will be

new EscapeBot(London, rand.nextInt(max_x - 1) + 1, rand.nextInt(max_y - 1) + 1, directions[rand.nextInt(directions.length)]);

Upvotes: 3

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