CODEWITHSUNDEEP
javascriptexception
konghou
konghou

Reputation: 557

continue javascript execution after error without a lot of try catch statements

let's say, i have 50 lines of javascript statements in a block. is there a way that the script continues to run if any one of the lines got an error, without using a lot of try catch blocks for each of the line?

Upvotes: 0

Views: 8069

Answers (2)

Andries
Andries

Reputation: 1527

Your question is a bit questionable. If you have 50 statements in a block which you allow to fail independently I conclude than that there is no relation between those statements. In this example 

var a = 1;
var b = a + 2;

the b variable relies on the outcome of a. If thats not the case, I assume, the only reason that those statements are placed in one block is that they must be executed at the same time. In that case, I also assume that those statements are more expressions like functions with side-effects, like C#-void functions or Actions. You don't really care about the outcome of the expressions..

You need to put each expression in a try-[catch | finally] block, I have no other option. To make it less verbose you can do something like below:

var tryF = function() {

    // convert arguments to normal array
    var args = [].slice.call(arguments, 0, arguments.length);

    // if has function to execute
    if(args.length > 0)
    {
      var func = args[0];//alert(func);
        try {func();}
        finally {

            // if has next function to execute
            if(args.length>1) {
             tryF.apply(null, args.slice(1, args.length));
            }
        }
    }
}
// usage
{
    // first function has a error, it won't block the next 
    tryF(function() { aslert(1); }, function() { alert(1); });
}

Upvotes: 1

Fabiotocchi
Fabiotocchi

Reputation: 216

Try this:

   1:  <head>
   2:  <script language="javascript">
   3:  function stoperror()
   4:  {
   5:  return true
   6:  }
   7:  window.onerror=stoperror();
   8:  </script>
   9:  </head>

Upvotes: 1

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