CODEWITHSUNDEEP
iphoneios
user1913674
user1913674

Reputation: 85

Counting same letters in a word

I need to count same letters in a word. For example: apple is my word and first I found whether 'a' exists in this letter or not. After that I want to count the number of 'a' in that word but I couldn't do that. This is my code which finds the specific letter;

if([originalString rangeOfString:compareString].location==NSNotFound)
{
    NSLog(@"Substring Not Found");
}

else
{
    NSLog(@"Substring Found Successfully");


}

originalString is a word which I took from my database randomly. So, how to count? Thanks for your help.

Upvotes: 0

Views: 185

Answers (3)

Manu
Manu

Reputation: 4750

NSString *strComplete = @"Appleeeeeeeeeeeeeee Appleeeeeeeee Aplleeeeeeeeee";
NSString *stringToFind = @"e";
NSArray *arySearch = [strComplete componentsSeparatedByString:stringToFind];
int countTheOccurrences = [arySearch count] - 1;

Output :

countTheOccurrences --- 34

Upvotes: 0

LeonardChallis
LeonardChallis

Reputation: 7783

You could just loop over the string once, adding each letter to an NSMutableDictionary (as the key) and keeping a tally of how many times the letter occurs (as the value).

The resulting NSMutableDictionary would hold the number of occurences for each unique letter, whereby you can extract what you like.

Upvotes: 0

Arun
Arun

Reputation: 3404

i have different idea let's try...

  NSString *string = @"appple";
    int times = [[string componentsSeparatedByString:@"p"] count]-1;

    NSLog(@"Counted times: %i", times);

Upvotes: 3

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