CODEWITHSUNDEEP
phpsessionecho
Keegs
Keegs

Reputation: 95

Take data from one php page and echo it onto another page

I need to simply take data from one page, upon a condition, and echo it on another page. Here is my code and my other attempts which do not work.

<?php
session_start;

/* connect to database */
$db = mysql_connect("localhost", "root", "root");
if (!$db)
    die('could not connect');

mysql_select_db('androidp2p')
    or die("could not select database");

/* variables */
$from = mysql_real_escape_string($_POST['from']); 
$to = mysql_real_escape_string($_POST['to']);
$message = mysql_real_escape_string($_POST['message']);

/* conditional code */
if ($_POST['to'])
{
    /* user wants to send a message */
    $query = "INSERT INTO messages (fromuser, touser, message) VALUES ('$from', '$to', '$message')";

    mysql_query($query)
        or die("\n\ndatabase error!\n". mysql_error());

    echo "ok. Messages have been saved.";
}
else 
{
    /* user wants to retrieve his messages*/
    $query = "SELECT * FROM messages WHERE touser='$from'";

    /* echo1 */
    echo $query;

    $result = mysql_query($query)
        or die("\n\ndatabase error!\n". mysql_error());

    $mailbox = array();

    while($row = mysql_fetch_assoc($result)){
    $mailbox[] = $row;
    }

    /* echo2 */
    echo "{ \"mailbox\":".json_encode($mailbox)." }";

    $name = "{ \"mailbox\":".json_encode($mailbox)." }";

    /* echo3 */
    echo $name;

    $_SESSION['myValue']=$name;
}

?>

And on the next php page, called test.php:

<?php

session_start;
echo $_SESSION['myValue'];

?>

My logcat shows that I am getting data in all three echos, but still nothing is being displayed on test.php(i.e. page2).

I also tried:

Attempt 1: In page 1:

session_start();
$_SESSION['myValue']=$name;

And in page2 used:

session_start();
echo $_SESSION['myValue'];

Attempt 2: In page 1:

session_start();
$_SESSION['name'] = $name ;

And in page2 used:

session_start();
$name = $_SESSION['name'];

Attempt 3: In page 1:

header("Location: test.php?name=".$name);

And in page2 used:

$name = $_GET['name'] ;

But nothing is being displayed on test.php(In this last attempt3 I got a bunch of warnings and maybe errors). What am I doing wrong?

This is my logCat:

04-13 14:46:22.564: I/RESPONSE(4591): SELECT * FROM messages WHERE touser='r' 04-13 14:46:22.564: I/RESPONSE(4591): { "mailbox":[{"id":"117","fromuser":"qw","touser":"r","message":"zx","timestamp":"2013-04-13 01:30:59"}] }

Now above I want you to see that touser is r. This entry into the db is what I want, i.e. all entries where the field "touser" contains the value "r".

Now, this is my test.php page:

{ "mailbox":[{"id":"123","fromuser":"r","touser":"","message":"","timestamp":"2013-04-13 13:41:23"},{"id":"122","fromuser":"r","touser":"","message":"","timestamp":"2013-04-13 13:30:53"}] }

As you would see, it returned all entries where the fromuser was r. Why do the two contradict each other??

Upvotes: 1

Views: 5217

Answers (1)

Derple
Derple

Reputation: 863

Not entirely sure what you are asking, but perhaps this will help.

In the beginning of your /* conditional code */

Use an isset condition....

<?php
session_start();

/* connect to database */
$db = mysql_connect("localhost", "root", "root");
if (!$db)
    die('could not connect');

mysql_select_db('androidp2p')
    or die("could not select database");

/* variables */
$from = mysql_real_escape_string($_POST['from']); 
$to = mysql_real_escape_string($_POST['to']);
$message = mysql_real_escape_string($_POST['message']);

/* conditional code */
if (isset ($_POST['to']))
{
    /* user wants to send a message */
    $query = "INSERT INTO messages (fromuser, touser, message) VALUES ('$from', '$to', '$message')";

    mysql_query($query)
        or die("\n\ndatabase error!\n". mysql_error());

    echo "ok. Messages have been saved.";
}
else 
{
    /* user wants to retrieve his messages*/
    $query = "SELECT * FROM messages WHERE touser='$from'";

    /* echo1 */
    echo $query;

    $result = mysql_query($query)
        or die("\n\ndatabase error!\n". mysql_error());

    $mailbox = array();

    while($row = mysql_fetch_assoc($result)){
    $mailbox[] = $row;
    }

    /* echo2 */
    echo "{ \"mailbox\":".json_encode($mailbox)." }";

    $name = "{ \"mailbox\":".json_encode($mailbox)." }";

    /* echo3 */
    //echo $name; no need to echo

    $_SESSION['myValue']=$name;
}

?>

Upvotes: 1

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