CODEWITHSUNDEEP
java
MrD
MrD

Reputation: 5086

Comparing characters

Suppose I have the following code:

String myString = "Hello";
char firstChar = myString.charAt(0);

I then want to check if firstChar has value "B". I tried

if(myChar == "b")

and 

if(myChar.equals("b"))

but none of these work.

What solution could I use?

Thanks in advance!

Upvotes: 2

Views: 280

Answers (4)

Grijesh Chauhan
Grijesh Chauhan

Reputation: 58271

"b" is not char but string to compare char you should write if(myChar == 'b')

Note: 

5   means number 
'5' means char 
"5" means string

all are different datatypes.

read: How do I compare strings in Java?

== compares reference equality. and .equals() tests for value equality.

read also this to check for upper or lower char: Find if first character in a string is upper case, Java

Upvotes: 3

Makoto
Makoto

Reputation: 106400

Characters work differently than String. You can't call methods on them, but you can compare them using ==.

If you want to compare either case, then you can use this:

if(myChar == 'b' || myChar == 'B')

Upvotes: 0

Shelef
Shelef

Reputation: 3827

You need to use the char literal by ':

if(myChar == 'b')

quotes(") represent strings. apostrophes(') represent characters

Upvotes: 0

Rob Audenaerde
Rob Audenaerde

Reputation: 20019

Use 'B'. Java is case sensitieve, and you neer to compare a char instead of String

Upvotes: 0

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